2/s-sqrt{2}= eching

$$\frac { 2 } { s - \sqrt { 2 } } =$$

Baholash

$$\frac{2}{s-\sqrt{2}}$$

Qisqa yechim qadamlari

\frac{2}{s-\sqrt{2}} maxrajini s+\sqrt{2} orqali surat va maxrajini koʻpaytirish orqali ratsionallashtiring.

$$\frac{2\left(s+\sqrt{2}\right)}{\left(s-\sqrt{2}\right)\left(s+\sqrt{2}\right)}$$

Hisoblang: \left(s-\sqrt{2}\right)\left(s+\sqrt{2}\right). Ko‘paytirish qoida yordamida turli kvadratlarga aylantirilishi mumkin: \left(a-b\right)\left(a+b\right)=a^{2}-b^{2}.

$$\frac{2\left(s+\sqrt{2}\right)}{s^{2}-\left(\sqrt{2}\right)^{2}}$$

\sqrt{2} kvadrati – 2.

$$\frac{2\left(s+\sqrt{2}\right)}{s^{2}-2}$$

2 ga s+\sqrt{2} ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$\frac{2s+2\sqrt{2}}{s^{2}-2}$$

s ga nisbatan hosilani topish

$$-\frac{2}{\left(s-\sqrt{2}\right)^{2}}$$