2/3-5x=bx+1/3 eching

$$\frac { 2 } { 3 } - 5 x = b x + \frac { 1 } { 3 }$$

b uchun yechish

$$b=-5+\frac{1}{3x}$$

$$x\neq 0$$

Chiziqli tenglamalarni yechish bo'yicha qadamlar

Tomonlarni almashtirib, barcha oʻzgaruvchi shartlar chap tomonga oʻtkazing.

$$bx+\frac{1}{3}=\frac{2}{3}-5x$$

Ikkala tarafdan \frac{1}{3} ni ayirish.

$$bx=\frac{2}{3}-5x-\frac{1}{3}$$

\frac{1}{3} olish uchun \frac{2}{3} dan \frac{1}{3} ni ayirish.

$$bx=\frac{1}{3}-5x$$

Tenglama standart shaklda.

$$xb=\frac{1}{3}-5x$$

Ikki tarafini x ga bo‘ling.

$$\frac{xb}{x}=\frac{\frac{1}{3}-5x}{x}$$

x ga bo'lish x ga ko'paytirishni bekor qiladi.

$$b=\frac{\frac{1}{3}-5x}{x}$$

\frac{1}{3}-5x ni x ga bo'lish.

$$b=-5+\frac{1}{3x}$$

x uchun yechish

$$x=\frac{1}{3\left(b+5\right)}$$

$$b\neq -5$$

Chiziqli tenglamalarni yechish bo'yicha qadamlar

Ikkala tarafdan bx ni ayirish.

$$\frac{2}{3}-5x-bx=\frac{1}{3}$$

Ikkala tarafdan \frac{2}{3} ni ayirish.

$$-5x-bx=\frac{1}{3}-\frac{2}{3}$$

-\frac{1}{3} olish uchun \frac{1}{3} dan \frac{2}{3} ni ayirish.

$$-5x-bx=-\frac{1}{3}$$

x'ga ega bo'lgan barcha shartlarni birlashtirish.

$$\left(-5-b\right)x=-\frac{1}{3}$$

Tenglama standart shaklda.

$$\left(-b-5\right)x=-\frac{1}{3}$$

Ikki tarafini -5-b ga bo‘ling.

$$\frac{\left(-b-5\right)x}{-b-5}=-\frac{\frac{1}{3}}{-b-5}$$

-5-b ga bo'lish -5-b ga ko'paytirishni bekor qiladi.

$$x=-\frac{\frac{1}{3}}{-b-5}$$

-\frac{1}{3} ni -5-b ga bo'lish.

$$x=\frac{1}{3\left(b+5\right)}$$