2/3*(x+1)=1/6*(x-2) eching

$$\frac { 2 } { 3 } \cdot ( x + 1 ) = \frac { 1 } { 6 } \cdot ( x - 2 )$$

x uchun yechish

$$x=-2$$

Chiziqli tenglamalarni yechish bo'yicha qadamlar

\frac{2}{3} ga x+1 ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$\frac{2}{3}x+\frac{2}{3}=\frac{1}{6}\left(x-2\right)$$

\frac{1}{6} ga x-2 ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$\frac{2}{3}x+\frac{2}{3}=\frac{1}{6}x+\frac{1}{6}\left(-2\right)$$

\frac{-2}{6} hosil qilish uchun \frac{1}{6} va -2 ni ko'paytirish.

$$\frac{2}{3}x+\frac{2}{3}=\frac{1}{6}x+\frac{-2}{6}$$

\frac{-2}{6} ulushini 2 ni chiqarib, bekor qilish hisobiga eng past shartlarga kamaytiring.

$$\frac{2}{3}x+\frac{2}{3}=\frac{1}{6}x-\frac{1}{3}$$

Ikkala tarafdan \frac{1}{6}x ni ayirish.

$$\frac{2}{3}x+\frac{2}{3}-\frac{1}{6}x=-\frac{1}{3}$$

\frac{1}{2}x ni olish uchun \frac{2}{3}x va -\frac{1}{6}x ni birlashtirish.

$$\frac{1}{2}x+\frac{2}{3}=-\frac{1}{3}$$

Ikkala tarafdan \frac{2}{3} ni ayirish.

$$\frac{1}{2}x=-\frac{1}{3}-\frac{2}{3}$$

-\frac{1}{3} va \frac{2}{3} da bir xil maxraji bor, ularning suratini ayirish orqali ayiring.

$$\frac{1}{2}x=\frac{-1-2}{3}$$

-3 olish uchun -1 dan 2 ni ayirish.

$$\frac{1}{2}x=\frac{-3}{3}$$

-1 ni olish uchun -3 ni 3 ga bo‘ling.

$$\frac{1}{2}x=-1$$

Ikki tarafini 2 va teskari kasri \frac{1}{2} ga ko‘paytiring.

$$x=-2$$