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1-\left(\frac{1}{6}\sqrt{24}-\frac{3}{8}\sqrt{12}\right)
1 ni olish uchun 2 ni 2 ga bo‘ling.
1-\left(\frac{1}{6}\times 2\sqrt{6}-\frac{3}{8}\sqrt{12}\right)
Faktor: 24=2^{2}\times 6. \sqrt{2^{2}\times 6} koʻpaytmasining kvadrat ildizini \sqrt{2^{2}}\sqrt{6} kvadrat ildizlarining koʻpaytmasi sifatida qayta yozing. 2^{2} ning kvadrat ildizini chiqarish.
1-\left(\frac{2}{6}\sqrt{6}-\frac{3}{8}\sqrt{12}\right)
\frac{2}{6} hosil qilish uchun \frac{1}{6} va 2 ni ko'paytirish.
1-\left(\frac{1}{3}\sqrt{6}-\frac{3}{8}\sqrt{12}\right)
\frac{2}{6} ulushini 2 ni chiqarib, bekor qilish hisobiga eng past shartlarga kamaytiring.
1-\left(\frac{1}{3}\sqrt{6}-\frac{3}{8}\times 2\sqrt{3}\right)
Faktor: 12=2^{2}\times 3. \sqrt{2^{2}\times 3} koʻpaytmasining kvadrat ildizini \sqrt{2^{2}}\sqrt{3} kvadrat ildizlarining koʻpaytmasi sifatida qayta yozing. 2^{2} ning kvadrat ildizini chiqarish.
1-\left(\frac{1}{3}\sqrt{6}+\frac{-3\times 2}{8}\sqrt{3}\right)
-\frac{3}{8}\times 2 ni yagona kasrga aylantiring.
1-\left(\frac{1}{3}\sqrt{6}+\frac{-6}{8}\sqrt{3}\right)
-6 hosil qilish uchun -3 va 2 ni ko'paytirish.
1-\left(\frac{1}{3}\sqrt{6}-\frac{3}{4}\sqrt{3}\right)
\frac{-6}{8} ulushini 2 ni chiqarib, bekor qilish hisobiga eng past shartlarga kamaytiring.
1-\frac{1}{3}\sqrt{6}-\left(-\frac{3}{4}\sqrt{3}\right)
\frac{1}{3}\sqrt{6}-\frac{3}{4}\sqrt{3} teskarisini topish uchun har birining teskarisini toping.
1-\frac{1}{3}\sqrt{6}+\frac{3}{4}\sqrt{3}
-\frac{3}{4}\sqrt{3} ning teskarisi \frac{3}{4}\sqrt{3} ga teng.