133/v-1/40=133-1/-20 eching

$$\frac { 133 } { v } - \frac { 1 } { 40 } = \frac { 133 - 1 } { - 20 }$$

v uchun yechish

$$v = -\frac{5320}{263} = -20\frac{60}{263} \approx -20,228136882$$

Chiziqli tenglamalarni yechish bo'yicha qadamlar

v qiymati 0 teng bo‘lmaydi, chunki nolga bo‘lish mumkin emas. Tenglamaning ikkala tarafini 40v ga, v,40,-20 ning eng kichik karralisiga ko‘paytiring.

$$40\times 133+40v\left(-\frac{1}{40}\right)=-2v\left(133-1\right)$$

5320 hosil qilish uchun 40 va 133 ni ko'paytirish.

$$5320+40v\left(-\frac{1}{40}\right)=-2v\left(133-1\right)$$

40 va 40 ni qisqartiring.

$$5320-v=-2v\left(133-1\right)$$

132 olish uchun 133 dan 1 ni ayirish.

$$5320-v=-2v\times 132$$

-264 hosil qilish uchun -2 va 132 ni ko'paytirish.

$$5320-v=-264v$$

264v ni ikki tarafga qo’shing.

$$5320-v+264v=0$$

263v ni olish uchun -v va 264v ni birlashtirish.

$$5320+263v=0$$

Ikkala tarafdan 5320 ni ayirish. Har qanday sonni noldan ayirsangiz, o‘zining manfiyi chiqadi.

$$263v=-5320$$

Ikki tarafini 263 ga bo‘ling.

$$v=\frac{-5320}{263}$$

\frac{-5320}{263} kasri manfiy belgini olib tashlash bilan -\frac{5320}{263} sifatida qayta yozilishi mumkin.

$$v=-\frac{5320}{263}$$