1-a^2/a+a-3=11 eching

$$\frac { 1 - a ^ { 2 } } { a } + a - 3 = 11$$

a uchun yechish

$$a=\frac{1}{14}\approx 0,071428571$$

Chiziqli tenglamalarni yechish bo'yicha qadamlar

a qiymati 0 teng bo‘lmaydi, chunki nolga bo‘lish mumkin emas. Tenglamaning ikkala tarafini a ga ko'paytirish.

$$1-a^{2}+aa+a\left(-3\right)=11a$$

a^{2} hosil qilish uchun a va a ni ko'paytirish.

$$1-a^{2}+a^{2}+a\left(-3\right)=11a$$

0 ni olish uchun -a^{2} va a^{2} ni birlashtirish.

$$1+a\left(-3\right)=11a$$

Ikkala tarafdan 11a ni ayirish.

$$1+a\left(-3\right)-11a=0$$

-14a ni olish uchun a\left(-3\right) va -11a ni birlashtirish.

$$1-14a=0$$

Ikkala tarafdan 1 ni ayirish. Har qanday sonni noldan ayirsangiz, o‘zining manfiyi chiqadi.

$$-14a=-1$$

Ikki tarafini -14 ga bo‘ling.

$$a=\frac{-1}{-14}$$

Ikkala surat va maxrajdan manfiy belgini olib tashlash bilan \frac{-1}{-14} kasrini \frac{1}{14} ga soddalashtirish mumkin.

$$a=\frac{1}{14}$$