1/R=1/R_{1}+1/R_{2} eching

$$\frac { 1 } { R } = \frac { 1 } { R _ { 1 } } + \frac { 1 } { R _ { 2 } }$$

R uchun yechish

$$R=\frac{R_{1}R_{2}}{R_{1}+R_{2}}$$

$$R_{2}\neq 0\text{ and }R_{1}\neq 0\text{ and }R_{1}\neq -R_{2}$$

Chiziqli tenglamalarni yechish bo'yicha qadamlar

R qiymati 0 teng bo‘lmaydi, chunki nolga bo‘lish mumkin emas. Tenglamaning ikkala tarafini RR_{1}R_{2} ga, R,R_{1},R_{2} ning eng kichik karralisiga ko‘paytiring.

$$R_{1}R_{2}=RR_{2}+RR_{1}$$

Tomonlarni almashtirib, barcha oʻzgaruvchi shartlar chap tomonga oʻtkazing.

$$RR_{2}+RR_{1}=R_{1}R_{2}$$

R'ga ega bo'lgan barcha shartlarni birlashtirish.

$$\left(R_{2}+R_{1}\right)R=R_{1}R_{2}$$

Tenglama standart shaklda.

$$\left(R_{1}+R_{2}\right)R=R_{1}R_{2}$$

Ikki tarafini R_{1}+R_{2} ga bo‘ling.

$$\frac{\left(R_{1}+R_{2}\right)R}{R_{1}+R_{2}}=\frac{R_{1}R_{2}}{R_{1}+R_{2}}$$

R_{1}+R_{2} ga bo'lish R_{1}+R_{2} ga ko'paytirishni bekor qiladi.

$$R=\frac{R_{1}R_{2}}{R_{1}+R_{2}}$$

R qiymati 0 teng bo‘lmaydi.

$$R=\frac{R_{1}R_{2}}{R_{1}+R_{2}}\text{, }R\neq 0$$

R_1 uchun yechish

$$R_{1}=-\frac{RR_{2}}{R-R_{2}}$$

$$R_{2}\neq 0\text{ and }R\neq 0\text{ and }R\neq R_{2}$$

Chiziqli tenglamalarni yechish bo'yicha qadamlar

R_{1} qiymati 0 teng bo‘lmaydi, chunki nolga bo‘lish mumkin emas. Tenglamaning ikkala tarafini RR_{1}R_{2} ga, R,R_{1},R_{2} ning eng kichik karralisiga ko‘paytiring.

$$R_{1}R_{2}=RR_{2}+RR_{1}$$

Ikkala tarafdan RR_{1} ni ayirish.

$$R_{1}R_{2}-RR_{1}=RR_{2}$$

R_{1}'ga ega bo'lgan barcha shartlarni birlashtirish.

$$\left(R_{2}-R\right)R_{1}=RR_{2}$$

Ikki tarafini R_{2}-R ga bo‘ling.

$$\frac{\left(R_{2}-R\right)R_{1}}{R_{2}-R}=\frac{RR_{2}}{R_{2}-R}$$

R_{2}-R ga bo'lish R_{2}-R ga ko'paytirishni bekor qiladi.

$$R_{1}=\frac{RR_{2}}{R_{2}-R}$$

R_{1} qiymati 0 teng bo‘lmaydi.

$$R_{1}=\frac{RR_{2}}{R_{2}-R}\text{, }R_{1}\neq 0$$