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Veb-qidiruvdagi o'xshash muammolar

Baham ko'rish

\frac{1\left(4-3i\right)}{\left(4+3i\right)\left(4-3i\right)}
Ham hisoblagich, ham maxrajni maxraj kompleksiga murakkablash orqali ko'paytirish, 4-3i.
\frac{1\left(4-3i\right)}{4^{2}-3^{2}i^{2}}
Ko‘paytirish qoida yordamida turli kvadratlarga aylantirilishi mumkin: \left(a-b\right)\left(a+b\right)=a^{2}-b^{2}.
\frac{1\left(4-3i\right)}{25}
Ta’rifi bo‘yicha, i^{2} – bu -1. Maxrajini hisoblang.
\frac{4-3i}{25}
4-3i hosil qilish uchun 1 va 4-3i ni ko'paytirish.
\frac{4}{25}-\frac{3}{25}i
\frac{4}{25}-\frac{3}{25}i ni olish uchun 4-3i ni 25 ga bo‘ling.
Re(\frac{1\left(4-3i\right)}{\left(4+3i\right)\left(4-3i\right)})
\frac{1}{4+3i}ning surat va maxrajini murakkab tutash maxraj 4-3i bilan ko‘paytiring.
Re(\frac{1\left(4-3i\right)}{4^{2}-3^{2}i^{2}})
Ko‘paytirish qoida yordamida turli kvadratlarga aylantirilishi mumkin: \left(a-b\right)\left(a+b\right)=a^{2}-b^{2}.
Re(\frac{1\left(4-3i\right)}{25})
Ta’rifi bo‘yicha, i^{2} – bu -1. Maxrajini hisoblang.
Re(\frac{4-3i}{25})
4-3i hosil qilish uchun 1 va 4-3i ni ko'paytirish.
Re(\frac{4}{25}-\frac{3}{25}i)
\frac{4}{25}-\frac{3}{25}i ni olish uchun 4-3i ni 25 ga bo‘ling.
\frac{4}{25}
\frac{4}{25}-\frac{3}{25}i ning real qismi – \frac{4}{25}.