1/3+1/2xleq5/6x-5/3 eching

$$\frac { 1 } { 3 } + \frac { 1 } { 2 } x \leq \frac { 5 } { 6 } x - \frac { 5 } { 3 }$$

x uchun yechish

$$x\geq 6$$

Yechim qadamlari

Ikkala tarafdan \frac{5}{6}x ni ayirish.

$$\frac{1}{3}+\frac{1}{2}x-\frac{5}{6}x\leq -\frac{5}{3}$$

-\frac{1}{3}x ni olish uchun \frac{1}{2}x va -\frac{5}{6}x ni birlashtirish.

$$\frac{1}{3}-\frac{1}{3}x\leq -\frac{5}{3}$$

Ikkala tarafdan \frac{1}{3} ni ayirish.

$$-\frac{1}{3}x\leq -\frac{5}{3}-\frac{1}{3}$$

-\frac{5}{3} va \frac{1}{3} da bir xil maxraji bor, ularning suratini ayirish orqali ayiring.

$$-\frac{1}{3}x\leq \frac{-5-1}{3}$$

-6 olish uchun -5 dan 1 ni ayirish.

$$-\frac{1}{3}x\leq \frac{-6}{3}$$

-2 ni olish uchun -6 ni 3 ga bo‘ling.

$$-\frac{1}{3}x\leq -2$$

Ikki tarafini -3 va teskari kasri -\frac{1}{3} ga ko‘paytiring. -\frac{1}{3} manfiy boʻlgani uchun tengsizlikning yo‘nalishi o‘zgaradi.

$$x\geq -2\left(-3\right)$$

6 hosil qilish uchun -2 va -3 ni ko'paytirish.

$$x\geq 6$$