1/2y-1/8>3/4+6/5y eching

$$\frac { 1 } { 2 } y - \frac { 1 } { 8 } > \frac { 3 } { 4 } + \frac { 6 } { 5 } y$$

y uchun yechish

$$y<-\frac{5}{4}$$

Yechim qadamlari

Ikkala tarafdan \frac{6}{5}y ni ayirish.

$$\frac{1}{2}y-\frac{1}{8}-\frac{6}{5}y>\frac{3}{4}$$

-\frac{7}{10}y ni olish uchun \frac{1}{2}y va -\frac{6}{5}y ni birlashtirish.

$$-\frac{7}{10}y-\frac{1}{8}>\frac{3}{4}$$

\frac{1}{8} ni ikki tarafga qo’shing.

$$-\frac{7}{10}y>\frac{3}{4}+\frac{1}{8}$$

4 va 8 ning eng kichik umumiy karralisi 8 ga teng. \frac{3}{4} va \frac{1}{8} ni 8 maxraj bilan kasrlarga aylantirib oling.

$$-\frac{7}{10}y>\frac{6}{8}+\frac{1}{8}$$

\frac{6}{8} va \frac{1}{8} da bir xil maxraji bor, ularning suratini qo‘shish orqali qo‘shing.

$$-\frac{7}{10}y>\frac{6+1}{8}$$

7 olish uchun 6 va 1'ni qo'shing.

$$-\frac{7}{10}y>\frac{7}{8}$$

Ikki tarafini -\frac{10}{7} va teskari kasri -\frac{7}{10} ga ko‘paytiring. -\frac{7}{10} <0 bo‘lganda, tengsizlikning yo‘nalishi o‘zgargan bo‘ladi.

$$y<\frac{7}{8}\left(-\frac{10}{7}\right)$$

Suratni maxrajga va maxrajini suratga ko‘paytirish orqali \frac{7}{8} ni -\frac{10}{7} ga ko‘paytiring.

$$y<\frac{7\left(-10\right)}{8\times 7}$$

Surat va maxrajdagi ikkala 7 ni qisqartiring.

$$y<\frac{-10}{8}$$

\frac{-10}{8} ulushini 2 ni chiqarib, bekor qilish hisobiga eng past shartlarga kamaytiring.

$$y<-\frac{5}{4}$$