1/2t-3/4<-2/5t+3/5 eching

$$\frac { 1 } { 2 } t - \frac { 3 } { 4 } < - \frac { 2 } { 5 } t + \frac { 3 } { 5 }$$

t uchun yechish

$$t<\frac{3}{2}$$

Yechim qadamlari

\frac{2}{5}t ni ikki tarafga qo’shing.

$$\frac{1}{2}t-\frac{3}{4}+\frac{2}{5}t<\frac{3}{5}$$

\frac{9}{10}t ni olish uchun \frac{1}{2}t va \frac{2}{5}t ni birlashtirish.

$$\frac{9}{10}t-\frac{3}{4}<\frac{3}{5}$$

\frac{3}{4} ni ikki tarafga qo’shing.

$$\frac{9}{10}t<\frac{3}{5}+\frac{3}{4}$$

5 va 4 ning eng kichik umumiy karralisi 20 ga teng. \frac{3}{5} va \frac{3}{4} ni 20 maxraj bilan kasrlarga aylantirib oling.

$$\frac{9}{10}t<\frac{12}{20}+\frac{15}{20}$$

\frac{12}{20} va \frac{15}{20} da bir xil maxraji bor, ularning suratini qo‘shish orqali qo‘shing.

$$\frac{9}{10}t<\frac{12+15}{20}$$

27 olish uchun 12 va 15'ni qo'shing.

$$\frac{9}{10}t<\frac{27}{20}$$

Ikki tarafini \frac{10}{9} va teskari kasri \frac{9}{10} ga ko‘paytiring. \frac{9}{10} musbat bo‘lgani uchun, tengsizlik yo‘nalishi o‘zgarmaydi.

$$t<\frac{27}{20}\times \frac{10}{9}$$

Suratni maxrajga va maxrajini suratga ko‘paytirish orqali \frac{27}{20} ni \frac{10}{9} ga ko‘paytiring.

$$t<\frac{27\times 10}{20\times 9}$$

\frac{27\times 10}{20\times 9} kasridagi ko‘paytirishlarni bajaring.

$$t<\frac{270}{180}$$

\frac{270}{180} ulushini 90 ni chiqarib, bekor qilish hisobiga eng past shartlarga kamaytiring.

$$t<\frac{3}{2}$$