1/(x^2+3)+1/(x+4)= eching

$$\frac { 1 } { ( x ^ { 2 } + 3 ) } + \frac { 1 } { ( x + 4 ) } =$$

Baholash

$$\frac{x^{2}+x+7}{\left(x+4\right)\left(x^{2}+3\right)}$$

Qisqa yechim qadamlari

Ifodalarni qo‘shish yoki ayirish uchun ularni yoyib, maxrajlarini bir xil qiling. x^{2}+3 va x+4 ning eng kichik umumiy karralisi \left(x+4\right)\left(x^{2}+3\right). \frac{1}{x^{2}+3} ni \frac{x+4}{x+4} marotabaga ko'paytirish. \frac{1}{x+4} ni \frac{x^{2}+3}{x^{2}+3} marotabaga ko'paytirish.

$$\frac{x+4}{\left(x+4\right)\left(x^{2}+3\right)}+\frac{x^{2}+3}{\left(x+4\right)\left(x^{2}+3\right)}$$

\frac{x+4}{\left(x+4\right)\left(x^{2}+3\right)} va \frac{x^{2}+3}{\left(x+4\right)\left(x^{2}+3\right)} da bir xil maxraji bor, ularning suratini qo‘shish orqali qo‘shing.

$$\frac{x+4+x^{2}+3}{\left(x+4\right)\left(x^{2}+3\right)}$$

x+4+x^{2}+3 kabi iboralarga o‘xshab birlashtiring.

$$\frac{x+7+x^{2}}{\left(x+4\right)\left(x^{2}+3\right)}$$

\left(x+4\right)\left(x^{2}+3\right) ni kengaytirish.

$$\frac{x+7+x^{2}}{x^{3}+4x^{2}+3x+12}$$

x ga nisbatan hosilani topish

$$-\frac{x^{4}+2x^{3}+22x^{2}+32x+9}{\left(\left(x+4\right)\left(x^{2}+3\right)\right)^{2}}$$