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\frac{\left(1+2i\right)\left(3+i\right)}{\left(3-i\right)\left(3+i\right)}
Ham hisoblagich, ham maxrajni maxraj kompleksiga murakkablash orqali ko'paytirish, 3+i.
\frac{\left(1+2i\right)\left(3+i\right)}{3^{2}-i^{2}}
Ko‘paytirish qoida yordamida turli kvadratlarga aylantirilishi mumkin: \left(a-b\right)\left(a+b\right)=a^{2}-b^{2}.
\frac{\left(1+2i\right)\left(3+i\right)}{10}
Ta’rifi bo‘yicha, i^{2} – bu -1. Maxrajini hisoblang.
\frac{1\times 3+i+2i\times 3+2i^{2}}{10}
Binomlarni ko‘paytirgandek 1+2i va 3+i murakkab sonlarni ko‘paytiring.
\frac{1\times 3+i+2i\times 3+2\left(-1\right)}{10}
Ta’rifi bo‘yicha, i^{2} – bu -1.
\frac{3+i+6i-2}{10}
1\times 3+i+2i\times 3+2\left(-1\right) ichidagi ko‘paytirishlarni bajaring.
\frac{3-2+\left(1+6\right)i}{10}
3+i+6i-2 ichida real va mavhum qismlarni birlashtiring.
\frac{1+7i}{10}
3-2+\left(1+6\right)i ichida qo‘shishlarni bajaring.
\frac{1}{10}+\frac{7}{10}i
\frac{1}{10}+\frac{7}{10}i ni olish uchun 1+7i ni 10 ga bo‘ling.
Re(\frac{\left(1+2i\right)\left(3+i\right)}{\left(3-i\right)\left(3+i\right)})
\frac{1+2i}{3-i}ning surat va maxrajini murakkab tutash maxraj 3+i bilan ko‘paytiring.
Re(\frac{\left(1+2i\right)\left(3+i\right)}{3^{2}-i^{2}})
Ko‘paytirish qoida yordamida turli kvadratlarga aylantirilishi mumkin: \left(a-b\right)\left(a+b\right)=a^{2}-b^{2}.
Re(\frac{\left(1+2i\right)\left(3+i\right)}{10})
Ta’rifi bo‘yicha, i^{2} – bu -1. Maxrajini hisoblang.
Re(\frac{1\times 3+i+2i\times 3+2i^{2}}{10})
Binomlarni ko‘paytirgandek 1+2i va 3+i murakkab sonlarni ko‘paytiring.
Re(\frac{1\times 3+i+2i\times 3+2\left(-1\right)}{10})
Ta’rifi bo‘yicha, i^{2} – bu -1.
Re(\frac{3+i+6i-2}{10})
1\times 3+i+2i\times 3+2\left(-1\right) ichidagi ko‘paytirishlarni bajaring.
Re(\frac{3-2+\left(1+6\right)i}{10})
3+i+6i-2 ichida real va mavhum qismlarni birlashtiring.
Re(\frac{1+7i}{10})
3-2+\left(1+6\right)i ichida qo‘shishlarni bajaring.
Re(\frac{1}{10}+\frac{7}{10}i)
\frac{1}{10}+\frac{7}{10}i ni olish uchun 1+7i ni 10 ga bo‘ling.
\frac{1}{10}
\frac{1}{10}+\frac{7}{10}i ning real qismi – \frac{1}{10}.