1+1/2-i eching

$$\frac { 1 + 1 } { 2 - i }$$

Baholash

$$\frac{4}{5}+\frac{2}{5}i=0,8+0,4i$$

Yechim qadamlari

2 olish uchun 1 va 1'ni qo'shing.

$$\frac{2}{2-i}$$

Ham hisoblagich, ham maxrajni maxraj kompleksiga murakkablash orqali ko'paytirish, 2+i.

$$\frac{2\left(2+i\right)}{\left(2-i\right)\left(2+i\right)}$$

Ko‘paytirish qoida yordamida turli kvadratlarga aylantirilishi mumkin: \left(a-b\right)\left(a+b\right)=a^{2}-b^{2}.

$$\frac{2\left(2+i\right)}{2^{2}-i^{2}}$$

Ta’rifi bo‘yicha, i^{2} – bu -1. Maxrajini hisoblang.

$$\frac{2\left(2+i\right)}{5}$$

2 ni 2+i marotabaga ko'paytirish.

$$\frac{2\times 2+2i}{5}$$

2\times 2+2i ichidagi ko‘paytirishlarni bajaring.

$$\frac{4+2i}{5}$$

\frac{4}{5}+\frac{2}{5}i ni olish uchun 4+2i ni 5 ga bo‘ling.

$$\frac{4}{5}+\frac{2}{5}i$$

Ashyoviy qism

$$\frac{4}{5} = 0,8$$

Yechim qadamlari

2 olish uchun 1 va 1'ni qo'shing.

$$Re(\frac{2}{2-i})$$

\frac{2}{2-i}ning surat va maxrajini murakkab tutash maxraj 2+i bilan ko‘paytiring.

$$Re(\frac{2\left(2+i\right)}{\left(2-i\right)\left(2+i\right)})$$

Ko‘paytirish qoida yordamida turli kvadratlarga aylantirilishi mumkin: \left(a-b\right)\left(a+b\right)=a^{2}-b^{2}.

$$Re(\frac{2\left(2+i\right)}{2^{2}-i^{2}})$$

Ta’rifi bo‘yicha, i^{2} – bu -1. Maxrajini hisoblang.

$$Re(\frac{2\left(2+i\right)}{5})$$

2 ni 2+i marotabaga ko'paytirish.

$$Re(\frac{2\times 2+2i}{5})$$

2\times 2+2i ichidagi ko‘paytirishlarni bajaring.

$$Re(\frac{4+2i}{5})$$

\frac{4}{5}+\frac{2}{5}i ni olish uchun 4+2i ni 5 ga bo‘ling.

$$Re(\frac{4}{5}+\frac{2}{5}i)$$

\frac{4}{5}+\frac{2}{5}i ning real qismi – \frac{4}{5}.

$$\frac{4}{5}$$