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\frac{211}{34}=\frac{1\times 10^{-5}\times 2\times 0\times 0\times 86}{16\times 10^{-3}\times 60\times 0\times 0\times 955}
Surat va maxrajdagi ikkala 0 ni qisqartiring.
\frac{211}{34}=\frac{86\times 10^{-5}}{955\times 10^{-3}}
Surat va maxrajdagi ikkala 0 ni qisqartiring.
\frac{211}{34}=\frac{86}{955\times 10^{2}}
Ayni asosning daraja ko‘rsatkichini bo‘lish uchun suratning darajasini maxraj darajasiga bo‘ling.
\frac{211}{34}=\frac{86}{955\times 100}
2 daraja ko‘rsatkichini 10 ga hisoblang va 100 ni qiymatni oling.
\frac{211}{34}=\frac{86}{95500}
95500 hosil qilish uchun 955 va 100 ni ko'paytirish.
\frac{211}{34}=\frac{43}{47750}
\frac{86}{95500} ulushini 2 ni chiqarib, bekor qilish hisobiga eng past shartlarga kamaytiring.
\frac{5037625}{811750}=\frac{731}{811750}
34 va 47750 ning eng kichik umumiy karralisi 811750 ga teng. \frac{211}{34} va \frac{43}{47750} ni 811750 maxraj bilan kasrlarga aylantirib oling.
\text{false}
\frac{5037625}{811750} va \frac{731}{811750} ni taqqoslang.