(5-i)/[(2+1)^2]^2 eching

$$\frac { ( 5 - i ) } { [ ( 2 + 1 ) ^ { 2 } ] ^ { 2 } }$$

Ashyoviy qism

$$\frac{5}{81} = 0,06172839506172839$$

Yechim qadamlari

Daraja ko‘rsatkichini boshqa ko‘rsatkichga oshirish uchun, darajalarini ko‘paytiring. 2 va 2 ni ko‘paytirib, 4 ni oling.

$$Re(\frac{5-i}{\left(2+1\right)^{4}})$$

3 olish uchun 2 va 1'ni qo'shing.

$$Re(\frac{5-i}{3^{4}})$$

4 daraja ko‘rsatkichini 3 ga hisoblang va 81 ni qiymatni oling.

$$Re(\frac{5-i}{81})$$

\frac{5}{81}-\frac{1}{81}i ni olish uchun 5-i ni 81 ga bo‘ling.

$$Re(\frac{5}{81}-\frac{1}{81}i)$$

\frac{5}{81}-\frac{1}{81}i ning real qismi – \frac{5}{81}.

$$\frac{5}{81}$$

Baholash

$$\frac{5}{81}-\frac{1}{81}i\approx 0,061728395-0,012345679i$$