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3\left(2x+3-\left(5x-7\right)\right)=\left(6x+11\right)\left(-8\right)
x qiymati -\frac{11}{6} teng bo‘lmaydi, chunki nolga bo‘lish mumkin emas. Tenglamaning ikkala tarafini 3\left(6x+11\right) ga, 6x+11,3 ning eng kichik karralisiga ko‘paytiring.
3\left(2x+3-5x+7\right)=\left(6x+11\right)\left(-8\right)
5x-7 teskarisini topish uchun har birining teskarisini toping.
3\left(-3x+3+7\right)=\left(6x+11\right)\left(-8\right)
-3x ni olish uchun 2x va -5x ni birlashtirish.
3\left(-3x+10\right)=\left(6x+11\right)\left(-8\right)
10 olish uchun 3 va 7'ni qo'shing.
-9x+30=\left(6x+11\right)\left(-8\right)
3 ga -3x+10 ni ko'paytirish orqali distributiv xususiyatdan foydalanish.
-9x+30=-48x-88
6x+11 ga -8 ni ko'paytirish orqali distributiv xususiyatdan foydalanish.
-9x+30+48x=-88
48x ni ikki tarafga qo’shing.
39x+30=-88
39x ni olish uchun -9x va 48x ni birlashtirish.
39x=-88-30
Ikkala tarafdan 30 ni ayirish.
39x=-118
-118 olish uchun -88 dan 30 ni ayirish.
x=\frac{-118}{39}
Ikki tarafini 39 ga bo‘ling.
x=-\frac{118}{39}
\frac{-118}{39} kasri manfiy belgini olib tashlash bilan -\frac{118}{39} sifatida qayta yozilishi mumkin.