(2i^2-1)(i^3+2)/2-i eching

$$\frac { ( 2 i ^ { 2 } - 1 ) ( i ^ { 3 } + 2 ) } { 2 - i }$$

Baholash

$$-3$$

Yechim qadamlari

2 daraja ko‘rsatkichini i ga hisoblang va -1 ni qiymatni oling.

$$\frac{\left(2\left(-1\right)-1\right)\left(i^{3}+2\right)}{2-i}$$

-2 hosil qilish uchun 2 va -1 ni ko'paytirish.

$$\frac{\left(-2-1\right)\left(i^{3}+2\right)}{2-i}$$

-3 olish uchun -2 dan 1 ni ayirish.

$$\frac{-3\left(i^{3}+2\right)}{2-i}$$

3 daraja ko‘rsatkichini i ga hisoblang va -i ni qiymatni oling.

$$\frac{-3\left(-i+2\right)}{2-i}$$

\left(-\frac{6}{5}-\frac{3}{5}i\right)\left(-i+2\right) ni olish uchun -3\left(-i+2\right) ni 2-i ga bo‘ling.

$$\left(-\frac{6}{5}-\frac{3}{5}i\right)\left(-i+2\right)$$

-\frac{6}{5}-\frac{3}{5}i ga -i+2 ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$-\frac{3}{5}+\frac{6}{5}i+\left(-\frac{12}{5}-\frac{6}{5}i\right)$$

-3 olish uchun -\frac{3}{5}+\frac{6}{5}i va -\frac{12}{5}-\frac{6}{5}i'ni qo'shing.

$$-3$$

Ashyoviy qism

$$-3$$

Yechim qadamlari

2 daraja ko‘rsatkichini i ga hisoblang va -1 ni qiymatni oling.

$$Re(\frac{\left(2\left(-1\right)-1\right)\left(i^{3}+2\right)}{2-i})$$

-2 hosil qilish uchun 2 va -1 ni ko'paytirish.

$$Re(\frac{\left(-2-1\right)\left(i^{3}+2\right)}{2-i})$$

-3 olish uchun -2 dan 1 ni ayirish.

$$Re(\frac{-3\left(i^{3}+2\right)}{2-i})$$

3 daraja ko‘rsatkichini i ga hisoblang va -i ni qiymatni oling.

$$Re(\frac{-3\left(-i+2\right)}{2-i})$$

\left(-\frac{6}{5}-\frac{3}{5}i\right)\left(-i+2\right) ni olish uchun -3\left(-i+2\right) ni 2-i ga bo‘ling.

$$Re(\left(-\frac{6}{5}-\frac{3}{5}i\right)\left(-i+2\right))$$

-\frac{6}{5}-\frac{3}{5}i ga -i+2 ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$Re(-\frac{3}{5}+\frac{6}{5}i+\left(-\frac{12}{5}-\frac{6}{5}i\right))$$

-3 olish uchun -\frac{3}{5}+\frac{6}{5}i va -\frac{12}{5}-\frac{6}{5}i'ni qo'shing.

$$Re(-3)$$

-3 ning real qismi – -3.

$$-3$$