frac{sqrt{3452}}{260}*7^3/55+1/55 eching

$$\frac { \sqrt { 3452 } } { 260 } \times \frac { 7 ^ { 3 } } { 55 } + \frac { 1 } { 55 }$$

Baholash

$$\frac{343\sqrt{863}}{7150}+\frac{1}{55}\approx 1,427449447$$

Yechim qadamlari

Faktor: 3452=2^{2}\times 863. \sqrt{2^{2}\times 863} koʻpaytmasining kvadrat ildizini \sqrt{2^{2}}\sqrt{863} kvadrat ildizlarining koʻpaytmasi sifatida qayta yozing. 2^{2} ning kvadrat ildizini chiqarish.

$$\frac{2\sqrt{863}}{260}\times \frac{7^{3}}{55}+\frac{1}{55}$$

\frac{1}{130}\sqrt{863} ni olish uchun 2\sqrt{863} ni 260 ga bo‘ling.

$$\frac{1}{130}\sqrt{863}\times \frac{7^{3}}{55}+\frac{1}{55}$$

3 daraja ko‘rsatkichini 7 ga hisoblang va 343 ni qiymatni oling.

$$\frac{1}{130}\sqrt{863}\times \frac{343}{55}+\frac{1}{55}$$

Suratni maxrajga va maxrajini suratga ko‘paytirish orqali \frac{1}{130} ni \frac{343}{55} ga ko‘paytiring.

$$\frac{1\times 343}{130\times 55}\sqrt{863}+\frac{1}{55}$$

\frac{1\times 343}{130\times 55} kasridagi ko‘paytirishlarni bajaring.

$$\frac{343}{7150}\sqrt{863}+\frac{1}{55}$$

Omil

$$\frac{343 \sqrt{863} + 130}{7150} = 1,4274494466567704$$