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\frac{\sqrt{3}-1}{\sqrt{3}+1}\times 1
1 ni olish uchun \sqrt{3}+1 ni \sqrt{3}+1 ga bo‘ling.
\frac{\left(\sqrt{3}-1\right)\left(\sqrt{3}-1\right)}{\left(\sqrt{3}+1\right)\left(\sqrt{3}-1\right)}\times 1
\frac{\sqrt{3}-1}{\sqrt{3}+1} maxrajini \sqrt{3}-1 orqali surat va maxrajini koʻpaytirish orqali ratsionallashtiring.
\frac{\left(\sqrt{3}-1\right)\left(\sqrt{3}-1\right)}{\left(\sqrt{3}\right)^{2}-1^{2}}\times 1
Hisoblang: \left(\sqrt{3}+1\right)\left(\sqrt{3}-1\right). Ko‘paytirish qoida yordamida turli kvadratlarga aylantirilishi mumkin: \left(a-b\right)\left(a+b\right)=a^{2}-b^{2}.
\frac{\left(\sqrt{3}-1\right)\left(\sqrt{3}-1\right)}{3-1}\times 1
\sqrt{3} kvadratini chiqarish. 1 kvadratini chiqarish.
\frac{\left(\sqrt{3}-1\right)\left(\sqrt{3}-1\right)}{2}\times 1
2 olish uchun 3 dan 1 ni ayirish.
\frac{\left(\sqrt{3}-1\right)^{2}}{2}\times 1
\left(\sqrt{3}-1\right)^{2} hosil qilish uchun \sqrt{3}-1 va \sqrt{3}-1 ni ko'paytirish.
\frac{\left(\sqrt{3}\right)^{2}-2\sqrt{3}+1}{2}\times 1
\left(a-b\right)^{2}=a^{2}-2ab+b^{2} binom teoremasini \left(\sqrt{3}-1\right)^{2} kengaytirilishi uchun ishlating.
\frac{3-2\sqrt{3}+1}{2}\times 1
\sqrt{3} kvadrati – 3.
\frac{4-2\sqrt{3}}{2}\times 1
4 olish uchun 3 va 1'ni qo'shing.
\left(2-\sqrt{3}\right)\times 1
2-\sqrt{3} natijani olish uchun 4-2\sqrt{3} ning har bir ifodasini 2 ga bo‘ling.
2-\sqrt{3}
2-\sqrt{3} ga 1 ni ko'paytirish orqali distributiv xususiyatdan foydalanish.