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\frac{\left(\sqrt{3}-\sqrt{7}\right)\left(\sqrt{3}-\sqrt{7}\right)}{\left(\sqrt{3}+\sqrt{7}\right)\left(\sqrt{3}-\sqrt{7}\right)}
\frac{\sqrt{3}-\sqrt{7}}{\sqrt{3}+\sqrt{7}} maxrajini \sqrt{3}-\sqrt{7} orqali surat va maxrajini koʻpaytirish orqali ratsionallashtiring.
\frac{\left(\sqrt{3}-\sqrt{7}\right)\left(\sqrt{3}-\sqrt{7}\right)}{\left(\sqrt{3}\right)^{2}-\left(\sqrt{7}\right)^{2}}
Hisoblang: \left(\sqrt{3}+\sqrt{7}\right)\left(\sqrt{3}-\sqrt{7}\right). Ko‘paytirish qoida yordamida turli kvadratlarga aylantirilishi mumkin: \left(a-b\right)\left(a+b\right)=a^{2}-b^{2}.
\frac{\left(\sqrt{3}-\sqrt{7}\right)\left(\sqrt{3}-\sqrt{7}\right)}{3-7}
\sqrt{3} kvadratini chiqarish. \sqrt{7} kvadratini chiqarish.
\frac{\left(\sqrt{3}-\sqrt{7}\right)\left(\sqrt{3}-\sqrt{7}\right)}{-4}
-4 olish uchun 3 dan 7 ni ayirish.
\frac{\left(\sqrt{3}-\sqrt{7}\right)^{2}}{-4}
\left(\sqrt{3}-\sqrt{7}\right)^{2} hosil qilish uchun \sqrt{3}-\sqrt{7} va \sqrt{3}-\sqrt{7} ni ko'paytirish.
\frac{\left(\sqrt{3}\right)^{2}-2\sqrt{3}\sqrt{7}+\left(\sqrt{7}\right)^{2}}{-4}
\left(a-b\right)^{2}=a^{2}-2ab+b^{2} binom teoremasini \left(\sqrt{3}-\sqrt{7}\right)^{2} kengaytirilishi uchun ishlating.
\frac{3-2\sqrt{3}\sqrt{7}+\left(\sqrt{7}\right)^{2}}{-4}
\sqrt{3} kvadrati – 3.
\frac{3-2\sqrt{21}+\left(\sqrt{7}\right)^{2}}{-4}
\sqrt{3} va \sqrt{7} ni koʻpaytirish uchun kvadrat ildiz ichidagi sonlarni koʻpaytiring.
\frac{3-2\sqrt{21}+7}{-4}
\sqrt{7} kvadrati – 7.
\frac{10-2\sqrt{21}}{-4}
10 olish uchun 3 va 7'ni qo'shing.