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\frac{\left(\sqrt{3}-\sqrt{2}\right)\left(\sqrt{2}-\sqrt{3}\right)}{\left(\sqrt{2}+\sqrt{3}\right)\left(\sqrt{2}-\sqrt{3}\right)}
\frac{\sqrt{3}-\sqrt{2}}{\sqrt{2}+\sqrt{3}} maxrajini \sqrt{2}-\sqrt{3} orqali surat va maxrajini koʻpaytirish orqali ratsionallashtiring.
\frac{\left(\sqrt{3}-\sqrt{2}\right)\left(\sqrt{2}-\sqrt{3}\right)}{\left(\sqrt{2}\right)^{2}-\left(\sqrt{3}\right)^{2}}
Hisoblang: \left(\sqrt{2}+\sqrt{3}\right)\left(\sqrt{2}-\sqrt{3}\right). Ko‘paytirish qoida yordamida turli kvadratlarga aylantirilishi mumkin: \left(a-b\right)\left(a+b\right)=a^{2}-b^{2}.
\frac{\left(\sqrt{3}-\sqrt{2}\right)\left(\sqrt{2}-\sqrt{3}\right)}{2-3}
\sqrt{2} kvadratini chiqarish. \sqrt{3} kvadratini chiqarish.
\frac{\left(\sqrt{3}-\sqrt{2}\right)\left(\sqrt{2}-\sqrt{3}\right)}{-1}
-1 olish uchun 2 dan 3 ni ayirish.
-\left(\sqrt{3}-\sqrt{2}\right)\left(\sqrt{2}-\sqrt{3}\right)
Istalgan sonni -1 ga boʻlsangiz, uning qarama-qarshisi chiqadi.
-\left(\sqrt{3}\sqrt{2}-\left(\sqrt{3}\right)^{2}-\left(\sqrt{2}\right)^{2}+\sqrt{3}\sqrt{2}\right)
\sqrt{3}-\sqrt{2} ifodaning har bir elementini \sqrt{2}-\sqrt{3} ifodaning har bir elementiga ko‘paytirish orqali taqsimot qonuni xususiyatlarini qo‘llash mumkin.
-\left(\sqrt{6}-\left(\sqrt{3}\right)^{2}-\left(\sqrt{2}\right)^{2}+\sqrt{3}\sqrt{2}\right)
\sqrt{3} va \sqrt{2} ni koʻpaytirish uchun kvadrat ildiz ichidagi sonlarni koʻpaytiring.
-\left(\sqrt{6}-3-\left(\sqrt{2}\right)^{2}+\sqrt{3}\sqrt{2}\right)
\sqrt{3} kvadrati – 3.
-\left(\sqrt{6}-3-2+\sqrt{3}\sqrt{2}\right)
\sqrt{2} kvadrati – 2.
-\left(\sqrt{6}-5+\sqrt{3}\sqrt{2}\right)
-5 olish uchun -3 dan 2 ni ayirish.
-\left(\sqrt{6}-5+\sqrt{6}\right)
\sqrt{3} va \sqrt{2} ni koʻpaytirish uchun kvadrat ildiz ichidagi sonlarni koʻpaytiring.
-\left(2\sqrt{6}-5\right)
2\sqrt{6} ni olish uchun \sqrt{6} va \sqrt{6} ni birlashtirish.
-2\sqrt{6}-\left(-5\right)
2\sqrt{6}-5 teskarisini topish uchun har birining teskarisini toping.
-2\sqrt{6}+5
-5 ning teskarisi 5 ga teng.