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\frac{\sqrt{2}\left(2\sqrt{2}+1\right)}{\left(2\sqrt{2}-1\right)\left(2\sqrt{2}+1\right)}
\frac{\sqrt{2}}{2\sqrt{2}-1} maxrajini 2\sqrt{2}+1 orqali surat va maxrajini koʻpaytirish orqali ratsionallashtiring.
\frac{\sqrt{2}\left(2\sqrt{2}+1\right)}{\left(2\sqrt{2}\right)^{2}-1^{2}}
Hisoblang: \left(2\sqrt{2}-1\right)\left(2\sqrt{2}+1\right). Ko‘paytirish qoida yordamida turli kvadratlarga aylantirilishi mumkin: \left(a-b\right)\left(a+b\right)=a^{2}-b^{2}.
\frac{\sqrt{2}\left(2\sqrt{2}+1\right)}{2^{2}\left(\sqrt{2}\right)^{2}-1^{2}}
\left(2\sqrt{2}\right)^{2} ni kengaytirish.
\frac{\sqrt{2}\left(2\sqrt{2}+1\right)}{4\left(\sqrt{2}\right)^{2}-1^{2}}
2 daraja ko‘rsatkichini 2 ga hisoblang va 4 ni qiymatni oling.
\frac{\sqrt{2}\left(2\sqrt{2}+1\right)}{4\times 2-1^{2}}
\sqrt{2} kvadrati – 2.
\frac{\sqrt{2}\left(2\sqrt{2}+1\right)}{8-1^{2}}
8 hosil qilish uchun 4 va 2 ni ko'paytirish.
\frac{\sqrt{2}\left(2\sqrt{2}+1\right)}{8-1}
2 daraja ko‘rsatkichini 1 ga hisoblang va 1 ni qiymatni oling.
\frac{\sqrt{2}\left(2\sqrt{2}+1\right)}{7}
7 olish uchun 8 dan 1 ni ayirish.
\frac{2\left(\sqrt{2}\right)^{2}+\sqrt{2}}{7}
\sqrt{2} ga 2\sqrt{2}+1 ni ko'paytirish orqali distributiv xususiyatdan foydalanish.
\frac{2\times 2+\sqrt{2}}{7}
\sqrt{2} kvadrati – 2.
\frac{4+\sqrt{2}}{7}
4 hosil qilish uchun 2 va 2 ni ko'paytirish.