frac{{(sqrt{169}-4)*(1+sqrt{25})}}{(sqrt{49}-1)}+sqrt{sqrt[3]{729}} eching

$$\frac { \{ ( \sqrt { 169 } - 4 ) \cdot ( 1 + \sqrt { 25 } ) \} } { ( \sqrt { 49 } - 1 ) } + \sqrt { \sqrt[ 3 ] { 729 } }$$

Baholash

$$12$$

Yechim qadamlari

169 ning kvadrat ildizini hisoblab, 13 natijaga ega bo‘ling.

$$\frac{\left(13-4\right)\left(1+\sqrt{25}\right)}{\sqrt{49}-1}+\sqrt{\sqrt[3]{729}}$$

9 olish uchun 13 dan 4 ni ayirish.

$$\frac{9\left(1+\sqrt{25}\right)}{\sqrt{49}-1}+\sqrt{\sqrt[3]{729}}$$

25 ning kvadrat ildizini hisoblab, 5 natijaga ega bo‘ling.

$$\frac{9\left(1+5\right)}{\sqrt{49}-1}+\sqrt{\sqrt[3]{729}}$$

6 olish uchun 1 va 5'ni qo'shing.

$$\frac{9\times 6}{\sqrt{49}-1}+\sqrt{\sqrt[3]{729}}$$

54 hosil qilish uchun 9 va 6 ni ko'paytirish.

$$\frac{54}{\sqrt{49}-1}+\sqrt{\sqrt[3]{729}}$$

49 ning kvadrat ildizini hisoblab, 7 natijaga ega bo‘ling.

$$\frac{54}{7-1}+\sqrt{\sqrt[3]{729}}$$

6 olish uchun 7 dan 1 ni ayirish.

$$\frac{54}{6}+\sqrt{\sqrt[3]{729}}$$

9 ni olish uchun 54 ni 6 ga bo‘ling.

$$9+\sqrt{\sqrt[3]{729}}$$

\sqrt[3]{729} ni hisoblab, 9 natijasiga ega bo‘ling.

$$9+\sqrt{9}$$

9 ning kvadrat ildizini hisoblab, 3 natijaga ega bo‘ling.

$$9+3$$

12 olish uchun 9 va 3'ni qo'shing.

$$12$$

Omil

$$2^{2}\times 3$$