delta(602^2)+4(602)+1 eching

$$\delta ( 602 ^ { 2 } ) + 4 ( 602 ) + 1$$

Baholash

$$362404\delta +2409$$

Yechim qadamlari

2 daraja ko‘rsatkichini 602 ga hisoblang va 362404 ni qiymatni oling.

$$\delta \times 362404+4\times 602+1$$

2408 hosil qilish uchun 4 va 602 ni ko'paytirish.

$$\delta \times 362404+2408+1$$

2409 olish uchun 2408 va 1'ni qo'shing.

$$\delta \times 362404+2409$$

δ ga nisbatan hosilani topish

$$362404$$

Yig'indi uchun derivativ qoidasidan foydalanish qadamlari

2 daraja ko‘rsatkichini 602 ga hisoblang va 362404 ni qiymatni oling.

$$\frac{\mathrm{d}}{\mathrm{d}\delta }(\delta \times 362404+4\times 602+1)$$

2408 hosil qilish uchun 4 va 602 ni ko'paytirish.

$$\frac{\mathrm{d}}{\mathrm{d}\delta }(\delta \times 362404+2408+1)$$

2409 olish uchun 2408 va 1'ni qo'shing.

$$\frac{\mathrm{d}}{\mathrm{d}\delta }(\delta \times 362404+2409)$$

Polinomialning hosilasi bu uning shartlari hosilasining yig‘indisiga teng. Konstant shartning hosilasi 0. ax^{n} ning hosilasi nax^{n-1}.

$$362404\delta ^{1-1}$$

1 dan 1 ni ayirish.

$$362404\delta ^{0}$$

Har qanday t sharti uchun (0 bundan mustasno) t^{0}=1.

$$362404\times 1$$

Har qanday t sharti uchun t\times 1=t va 1t=t.

$$362404$$