cosomegat=x/r.quadsinomegat=y/r eching

$$\cos \omega t = \frac { x } { r } . \quad \sin \omega t = \frac { y } { r }$$

r uchun yechish

$$\left\{\begin{matrix}r=\frac{x}{\cos(t\omega )}\text{, }&\left(\nexists n_{1}\in \mathrm{Z}\text{ : }\omega =\frac{\pi n_{1}}{t}+\frac{\pi }{2t}\text{ and }x\neq 0\right)\text{ or }\left(t=0\text{ and }x\neq 0\right)\\r\neq 0\text{, }&\exists n_{1}\in \mathrm{Z}\text{ : }n_{1}=\frac{t\omega }{\pi }-\frac{1}{2}\text{, }not(t=0)\text{ and }t\neq 0\text{ and }x=0\end{matrix}\right,$$

Chiziqli tenglamalarni yechish bo'yicha qadamlar

r qiymati 0 teng bo‘lmaydi, chunki nolga bo‘lish mumkin emas. Tenglamaning ikkala tarafini r ga ko'paytirish.

$$r\cos(\omega t)=x$$

Tenglama standart shaklda.

$$\cos(t\omega )r=x$$

Ikki tarafini \cos(\omega t) ga bo‘ling.

$$\frac{\cos(t\omega )r}{\cos(t\omega )}=\frac{x}{\cos(t\omega )}$$

\cos(\omega t) ga bo'lish \cos(\omega t) ga ko'paytirishni bekor qiladi.

$$r=\frac{x}{\cos(t\omega )}$$

r qiymati 0 teng bo‘lmaydi.

$$r=\frac{x}{\cos(t\omega )}\text{, }r\neq 0$$