Delta=4^2-4(4-10/3) eching

$$\Delta = 4 ^ { 2 } - 4 ( 4 - \frac { 10 } { 3 } )$$

Δ uchun yechish

$$\Delta =\frac{40}{3}\approx 13,333333333$$

Chiziqli tenglamalarni yechish bo'yicha qadamlar

2 daraja ko‘rsatkichini 4 ga hisoblang va 16 ni qiymatni oling.

$$\Delta =16-4\left(4-\frac{10}{3}\right)$$

4 ni \frac{12}{3} kasrga o‘giring.

$$\Delta =16-4\left(\frac{12}{3}-\frac{10}{3}\right)$$

\frac{12}{3} va \frac{10}{3} da bir xil maxraji bor, ularning suratini ayirish orqali ayiring.

$$\Delta =16-4\times \frac{12-10}{3}$$

2 olish uchun 12 dan 10 ni ayirish.

$$\Delta =16-4\times \frac{2}{3}$$

4\times \frac{2}{3} ni yagona kasrga aylantiring.

$$\Delta =16-\frac{4\times 2}{3}$$

8 hosil qilish uchun 4 va 2 ni ko'paytirish.

$$\Delta =16-\frac{8}{3}$$

16 ni \frac{48}{3} kasrga o‘giring.

$$\Delta =\frac{48}{3}-\frac{8}{3}$$

\frac{48}{3} va \frac{8}{3} da bir xil maxraji bor, ularning suratini ayirish orqali ayiring.

$$\Delta =\frac{48-8}{3}$$

40 olish uchun 48 dan 8 ni ayirish.

$$\Delta =\frac{40}{3}$$

Δ'ni tayinlash

$$\Delta ≔\frac{40}{3}$$