Delta=4^2-4(4(-10/3)) eching

$$\Delta = 4 ^ { 2 } - 4 ( 4 ( - \frac { 10 } { 3 } ) )$$

Δ uchun yechish

$$\Delta =\frac{208}{3}\approx 69,333333333$$

Chiziqli tenglamalarni yechish bo'yicha qadamlar

2 daraja ko‘rsatkichini 4 ga hisoblang va 16 ni qiymatni oling.

$$\Delta =16-4\times 4\left(-\frac{10}{3}\right)$$

16 hosil qilish uchun 4 va 4 ni ko'paytirish.

$$\Delta =16-16\left(-\frac{10}{3}\right)$$

16\left(-\frac{10}{3}\right) ni yagona kasrga aylantiring.

$$\Delta =16-\frac{16\left(-10\right)}{3}$$

-160 hosil qilish uchun 16 va -10 ni ko'paytirish.

$$\Delta =16-\frac{-160}{3}$$

\frac{-160}{3} kasri manfiy belgini olib tashlash bilan -\frac{160}{3} sifatida qayta yozilishi mumkin.

$$\Delta =16-\left(-\frac{160}{3}\right)$$

-\frac{160}{3} ning teskarisi \frac{160}{3} ga teng.

$$\Delta =16+\frac{160}{3}$$

16 ni \frac{48}{3} kasrga o‘giring.

$$\Delta =\frac{48}{3}+\frac{160}{3}$$

\frac{48}{3} va \frac{160}{3} da bir xil maxraji bor, ularning suratini qo‘shish orqali qo‘shing.

$$\Delta =\frac{48+160}{3}$$

208 olish uchun 48 va 160'ni qo'shing.

$$\Delta =\frac{208}{3}$$

Δ'ni tayinlash

$$\Delta ≔\frac{208}{3}$$