[-2+2*2+b^2-2]^3-(x^2-2)^3 eching

$$[ - 2 + 2 \times 2 + b ^ { 2 } - 2 ] ^ { 3 } - ( x ^ { 2 } - 2 ) ^ { 3 }$$

Baholash

$$\left(2+b^{2}-x^{2}\right)\left(b^{2}\left(x^{2}-2\right)+\left(x^{2}-2\right)^{2}+b^{4}\right)$$

Yechim qadamlari

4 hosil qilish uchun 2 va 2 ni ko'paytirish.

$$\left(-2+4+b^{2}-2\right)^{3}-\left(x^{2}-2\right)^{3}$$

2 olish uchun -2 va 4'ni qo'shing.

$$\left(2+b^{2}-2\right)^{3}-\left(x^{2}-2\right)^{3}$$

0 olish uchun 2 dan 2 ni ayirish.

$$\left(b^{2}\right)^{3}-\left(x^{2}-2\right)^{3}$$

\left(a-b\right)^{3}=a^{3}-3a^{2}b+3ab^{2}-b^{3} binom teoremasini \left(x^{2}-2\right)^{3} kengaytirilishi uchun ishlating.

$$\left(b^{2}\right)^{3}-\left(\left(x^{2}\right)^{3}-6\left(x^{2}\right)^{2}+12x^{2}-8\right)$$

Daraja ko‘rsatkichini boshqa ko‘rsatkichga oshirish uchun, darajalarini ko‘paytiring. 2 va 3 ni ko‘paytirib, 6 ni oling.

$$\left(b^{2}\right)^{3}-\left(x^{6}-6\left(x^{2}\right)^{2}+12x^{2}-8\right)$$

Daraja ko‘rsatkichini boshqa ko‘rsatkichga oshirish uchun, darajalarini ko‘paytiring. 2 va 2 ni ko‘paytirib, 4 ni oling.

$$\left(b^{2}\right)^{3}-\left(x^{6}-6x^{4}+12x^{2}-8\right)$$

x^{6}-6x^{4}+12x^{2}-8 teskarisini topish uchun har birining teskarisini toping.

$$\left(b^{2}\right)^{3}-x^{6}+6x^{4}-12x^{2}+8$$

Daraja ko‘rsatkichini boshqa ko‘rsatkichga oshirish uchun, darajalarini ko‘paytiring. 2 va 3 ni ko‘paytirib, 6 ni oling.

$$b^{6}-x^{6}+6x^{4}-12x^{2}+8$$

Kengaytirish

$$8+b^{6}-12x^{2}+6x^{4}-x^{6}$$

Yechim qadamlari

4 hosil qilish uchun 2 va 2 ni ko'paytirish.

$$\left(-2+4+b^{2}-2\right)^{3}-\left(x^{2}-2\right)^{3}$$

2 olish uchun -2 va 4'ni qo'shing.

$$\left(2+b^{2}-2\right)^{3}-\left(x^{2}-2\right)^{3}$$

0 olish uchun 2 dan 2 ni ayirish.

$$\left(b^{2}\right)^{3}-\left(x^{2}-2\right)^{3}$$

\left(a-b\right)^{3}=a^{3}-3a^{2}b+3ab^{2}-b^{3} binom teoremasini \left(x^{2}-2\right)^{3} kengaytirilishi uchun ishlating.

$$\left(b^{2}\right)^{3}-\left(\left(x^{2}\right)^{3}-6\left(x^{2}\right)^{2}+12x^{2}-8\right)$$

Daraja ko‘rsatkichini boshqa ko‘rsatkichga oshirish uchun, darajalarini ko‘paytiring. 2 va 3 ni ko‘paytirib, 6 ni oling.

$$\left(b^{2}\right)^{3}-\left(x^{6}-6\left(x^{2}\right)^{2}+12x^{2}-8\right)$$

Daraja ko‘rsatkichini boshqa ko‘rsatkichga oshirish uchun, darajalarini ko‘paytiring. 2 va 2 ni ko‘paytirib, 4 ni oling.

$$\left(b^{2}\right)^{3}-\left(x^{6}-6x^{4}+12x^{2}-8\right)$$

x^{6}-6x^{4}+12x^{2}-8 teskarisini topish uchun har birining teskarisini toping.

$$\left(b^{2}\right)^{3}-x^{6}+6x^{4}-12x^{2}+8$$

Daraja ko‘rsatkichini boshqa ko‘rsatkichga oshirish uchun, darajalarini ko‘paytiring. 2 va 3 ni ko‘paytirib, 6 ni oling.

$$b^{6}-x^{6}+6x^{4}-12x^{2}+8$$