[(-2)^{6}:(-2)^3]^3*(-2)*(-2)^-4=^* eching

$$[ ( - 2 ) ^ { 6 } : ( - 2 ) ^ { 3 } ] ^ { 3 } \cdot ( - 2 ) \cdot ( - 2 ) ^ { - 4 } = ^ { * }$$

Baholash

$$64$$

Yechim qadamlari

Ayni asosning daraja ko‘rsatkichini bo‘lish uchun maxrajning darajasini surat darajasidan ayiring. 6 dan 3 ni ayirib, 3 ni oling.

$$\left(\left(-2\right)^{3}\right)^{3}\left(-2\right)\left(-2\right)^{-4}$$

Daraja ko‘rsatkichini boshqa ko‘rsatkichga oshirish uchun, darajalarini ko‘paytiring. 3 va 3 ni ko‘paytirib, 9 ni oling.

$$\left(-2\right)^{9}\left(-2\right)\left(-2\right)^{-4}$$

Ayni asosning daraja ko‘rsatkichlarini ko‘paytirish uchun ularning darajalarini qo‘shing. 9 va 1 ni qo‘shib, 10 ni oling.

$$\left(-2\right)^{10}\left(-2\right)^{-4}$$

Ayni asosning daraja ko‘rsatkichlarini ko‘paytirish uchun ularning darajalarini qo‘shing. 10 va -4 ni qo‘shib, 6 ni oling.

$$\left(-2\right)^{6}$$

6 daraja ko‘rsatkichini -2 ga hisoblang va 64 ni qiymatni oling.

$$64$$

Omil

$$2^{6}$$