=-3x^2-8x-3 eching

$$= - 3 x ^ { 2 } - 8 x - 3$$

Omil

$$-3\left(x-\frac{-\sqrt{7}-4}{3}\right)\left(x-\frac{\sqrt{7}-4}{3}\right)$$

Kvadrat tenglamalaridan foydalanish qoidalari

Kvadrat koʻp tenglama bu orqali hisoblanadi: ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right), bu yerda x_{1} va x_{2} ax^{2}+bx+c=0 kvadrat tenglamaning yechimlari.

$$-3x^{2}-8x-3=0$$

ax^{2}+bx+c=0 shaklidagi barcha tenglamalarni kvadrat formulasi bilan yechish mumkin: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. Kvadrat formula ikki yechmni taqdim qiladi, biri ± qo'shish bo'lganda, va ikkinchisi ayiruv bo'lganda.

$$x=\frac{-\left(-8\right)±\sqrt{\left(-8\right)^{2}-4\left(-3\right)\left(-3\right)}}{2\left(-3\right)}$$

-8 kvadratini chiqarish.

$$x=\frac{-\left(-8\right)±\sqrt{64-4\left(-3\right)\left(-3\right)}}{2\left(-3\right)}$$

-4 ni -3 marotabaga ko'paytirish.

$$x=\frac{-\left(-8\right)±\sqrt{64+12\left(-3\right)}}{2\left(-3\right)}$$

12 ni -3 marotabaga ko'paytirish.

$$x=\frac{-\left(-8\right)±\sqrt{64-36}}{2\left(-3\right)}$$

64 ni -36 ga qo'shish.

$$x=\frac{-\left(-8\right)±\sqrt{28}}{2\left(-3\right)}$$

28 ning kvadrat ildizini chiqarish.

$$x=\frac{-\left(-8\right)±2\sqrt{7}}{2\left(-3\right)}$$

-8 ning teskarisi 8 ga teng.

$$x=\frac{8±2\sqrt{7}}{2\left(-3\right)}$$

2 ni -3 marotabaga ko'paytirish.

$$x=\frac{8±2\sqrt{7}}{-6}$$

x=\frac{8±2\sqrt{7}}{-6} tenglamasini yeching, bunda ± musbat. 8 ni 2\sqrt{7} ga qo'shish.

$$x=\frac{2\sqrt{7}+8}{-6}$$

8+2\sqrt{7} ni -6 ga bo'lish.

$$x=\frac{-\sqrt{7}-4}{3}$$

x=\frac{8±2\sqrt{7}}{-6} tenglamasini yeching, bunda ± manfiy. 8 dan 2\sqrt{7} ni ayirish.

$$x=\frac{8-2\sqrt{7}}{-6}$$

8-2\sqrt{7} ni -6 ga bo'lish.

$$x=\frac{\sqrt{7}-4}{3}$$

ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right) formulasi yordamida amalni hisoblang. x_{1} uchun \frac{-4-\sqrt{7}}{3} ga va x_{2} uchun \frac{-4+\sqrt{7}}{3} ga bo‘ling.

$$-3x^{2}-8x-3=-3\left(x-\frac{-\sqrt{7}-4}{3}\right)\left(x-\frac{\sqrt{7}-4}{3}\right)$$

Baholash

$$-3x^{2}-8x-3$$