=-[2/10b_{2}(2/10)+8/10log_{2}(8/10)] eching

$$= - [ \frac { 2 } { 10 } b _ { 2 } ( \frac { 2 } { 10 } ) + \frac { 8 } { 10 } \log _ { 2 } ( \frac { 8 } { 10 } ) ]$$

Baholash

$$-\frac{b_{2}}{25}+\frac{4\log_{2}\left(5\right)}{5}-\frac{8}{5}$$

Yechim qadamlari

\left(\frac{2}{10}\right)^{2} hosil qilish uchun \frac{2}{10} va \frac{2}{10} ni ko'paytirish.

$$-\left(\left(\frac{2}{10}\right)^{2}b_{2}+\frac{8}{10}\log_{2}\left(\frac{8}{10}\right)\right)$$

\frac{2}{10} ulushini 2 ni chiqarib, bekor qilish hisobiga eng past shartlarga kamaytiring.

$$-\left(\left(\frac{1}{5}\right)^{2}b_{2}+\frac{8}{10}\log_{2}\left(\frac{8}{10}\right)\right)$$

2 daraja ko‘rsatkichini \frac{1}{5} ga hisoblang va \frac{1}{25} ni qiymatni oling.

$$-\left(\frac{1}{25}b_{2}+\frac{8}{10}\log_{2}\left(\frac{8}{10}\right)\right)$$

\frac{8}{10} ulushini 2 ni chiqarib, bekor qilish hisobiga eng past shartlarga kamaytiring.

$$-\left(\frac{1}{25}b_{2}+\frac{4}{5}\log_{2}\left(\frac{8}{10}\right)\right)$$

\frac{8}{10} ulushini 2 ni chiqarib, bekor qilish hisobiga eng past shartlarga kamaytiring.

$$-\left(\frac{1}{25}b_{2}+\frac{4}{5}\log_{2}\left(\frac{4}{5}\right)\right)$$

\frac{1}{25}b_{2}+\frac{4}{5}\log_{2}\left(\frac{4}{5}\right) teskarisini topish uchun har birining teskarisini toping.

$$-\frac{1}{25}b_{2}-\frac{4}{5}\log_{2}\left(\frac{4}{5}\right)$$

Omil

$$\frac{-b_{2}+20\log_{2}\left(5\right)-40}{25}$$

Yechim qadamlari

Hisoblang: \frac{1}{5}\times \frac{1}{5}b_{2}+\frac{4}{5}\ln(\frac{4}{5})\ln(2)^{-1}. \frac{1}{25} omili.

$$\frac{b_{2}+20\log_{2}\left(\frac{4}{5}\right)}{25}$$

Toʻliq ajratilgan ifodani qaytadan yozing. Qisqartirish.

$$-\frac{b_{2}+20\log_{2}\left(\frac{4}{5}\right)}{25}$$