+b^{2}=3.a^2+c^2+ac=4.b^2+c^2-sqrt{3}ab=7 eching

$$+ b ^ { 2 } = 3 . a ^ { 2 } + c ^ { 2 } + a c = 4 . b ^ { 2 } + c ^ { 2 } - \sqrt { 3 } a b = 7$$

b uchun yechish

$$b=\sqrt{3}\approx 1,732050808$$

$$b=-\sqrt{3}\approx -1,732050808$$

Kvadrat ildizini topish bo'yicha qadamlar

Tenglamaning ikkala tarafining kvadrat ildizini chiqarish.

$$b=\sqrt{3} b=-\sqrt{3}$$

Kvadrat tenglamalaridan foydalanish qoidalari

Ikkala tarafdan 3 ni ayirish.

$$b^{2}-3=0$$

Ushbu tenglama standart shaklidadir: ax^{2}+bx+c=0. Kvadrat tenglama formulasida, \frac{-b±\sqrt{b^{2}-4ac}}{2a} 1 ni a, 0 ni b va -3 ni c bilan almashtiring.

$$b=\frac{0±\sqrt{0^{2}-4\left(-3\right)}}{2}$$

0 kvadratini chiqarish.

$$b=\frac{0±\sqrt{-4\left(-3\right)}}{2}$$

-4 ni -3 marotabaga ko'paytirish.

$$b=\frac{0±\sqrt{12}}{2}$$

12 ning kvadrat ildizini chiqarish.

$$b=\frac{0±2\sqrt{3}}{2}$$

b=\frac{0±2\sqrt{3}}{2} tenglamasini yeching, bunda ± musbat.

$$b=\sqrt{3}$$

b=\frac{0±2\sqrt{3}}{2} tenglamasini yeching, bunda ± manfiy.

$$b=-\sqrt{3}$$

Tenglama yechildi.

$$b=\sqrt{3} b=-\sqrt{3}$$