+(2k-1)x+k^2-1=0 eching

$$+ ( 2 k - 1 ) x + k ^ { 2 } - 1 = 0$$

x uchun yechish

$$x=-\frac{k^{2}-1}{2k-1}$$

$$k\neq \frac{1}{2}$$

Chiziqli tenglamalarni yechish bo'yicha qadamlar

2k-1 ga x ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$2kx-x+k^{2}-1=0$$

Ikkala tarafdan k^{2} ni ayirish. Har qanday sonni noldan ayirsangiz, o‘zining manfiyi chiqadi.

$$2kx-x-1=-k^{2}$$

1 ni ikki tarafga qo’shing.

$$2kx-x=-k^{2}+1$$

x'ga ega bo'lgan barcha shartlarni birlashtirish.

$$\left(2k-1\right)x=-k^{2}+1$$

Tenglama standart shaklda.

$$\left(2k-1\right)x=1-k^{2}$$

Ikki tarafini 2k-1 ga bo‘ling.

$$\frac{\left(2k-1\right)x}{2k-1}=\frac{1-k^{2}}{2k-1}$$

2k-1 ga bo'lish 2k-1 ga ko'paytirishni bekor qiladi.

$$x=\frac{1-k^{2}}{2k-1}$$

k uchun yechish

$$k=\sqrt{x^{2}+x+1}-x$$

$$k=-\sqrt{x^{2}+x+1}-x$$