θ=5,text{provethat}5sinθ-3cosθ=pm3 ھەل قىلىش

$$\theta = 5 , \text { prove that } 5 \sin \theta - 3 \cos \theta = \pm 3$$

θ، p، r، o، v، t، h، a نى يېشىش

$$\left\{\begin{matrix}\\r\neq 0\text{, }\theta =5\text{, }t\neq 0\text{, }p=\frac{±3+3\cos(5)}{5e\sin(5)ahorvt^{2}}\text{, }o\neq 0\text{, }v\neq 0\text{, }h\neq 0\text{, }a\neq 0\text{, }&\text{unconditionally}\\r=0\text{, }\theta =5\text{, }t\in \mathrm{R}\text{, }p\in \mathrm{R}\text{, }o\in \mathrm{R}\text{, }v\in \mathrm{R}\text{, }h\in \mathrm{R}\text{, }a\in \mathrm{R}\text{; }r\in \mathrm{R}\text{, }\theta =5\text{, }t\in \mathrm{R}\text{, }p\in \mathrm{R}\text{, }o=0\text{, }v\in \mathrm{R}\text{, }h\in \mathrm{R}\text{, }a\in \mathrm{R}\text{; }r\in \mathrm{R}\text{, }\theta =5\text{, }t\in \mathrm{R}\text{, }p\in \mathrm{R}\text{, }o\in \mathrm{R}\text{, }v=0\text{, }h\in \mathrm{R}\text{, }a\in \mathrm{R}\text{; }r\in \mathrm{R}\text{, }\theta =5\text{, }t\in \mathrm{R}\text{, }p\in \mathrm{R}\text{, }o\in \mathrm{R}\text{, }v\in \mathrm{R}\text{, }h=0\text{, }a\in \mathrm{R}\text{; }r\in \mathrm{R}\text{, }\theta =5\text{, }t\in \mathrm{R}\text{, }p\in \mathrm{R}\text{, }o\in \mathrm{R}\text{, }v\in \mathrm{R}\text{, }h\in \mathrm{R}\text{, }a=0\text{; }r\in \mathrm{R}\text{, }\theta =5\text{, }t=0\text{, }p\in \mathrm{R}\text{, }o\in \mathrm{R}\text{, }v\in \mathrm{R}\text{, }h\in \mathrm{R}\text{, }a\in \mathrm{R}\text{, }&-\left(±3\right)-3\cos(5)=0\end{matrix}\right.$$