z نى يېشىش
z=e^{2\left(Im(\frac{1}{x})+iRe(\frac{1}{x})\right)\left(\left(Re(x)\right)^{2}+\left(Im(x)\right)^{2}\right)arg(\left(\frac{x^{4}+1}{x^{3}}\right)^{\lfloor 1-x\rfloor })-4\pi n_{1}iRe(\frac{1}{x})\left(\left(Re(x)\right)^{2}+\left(Im(x)\right)^{2}\right)-4\pi Im(\frac{1}{x})n_{1}\left(\left(Re(x)\right)^{2}+\left(Im(x)\right)^{2}\right)}\left(|\left(\frac{x^{4}+1}{x^{3}}\right)^{\lfloor 1-x\rfloor }|\right)^{2\left(Re(\frac{1}{x})-iIm(\frac{1}{x})\right)\left(\left(Re(x)\right)^{2}+\left(Im(x)\right)^{2}\right)}
n_{1}\in \mathrm{Z}
x\neq 0
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