{l}{sin3/5cosbeta=-5/13}{cos(a-beta)=22} ھەل قىلىش

$$\left. \begin{array}{l}{ \sin \frac { 3 } { 5 } \cos \beta = - \frac { 5 } { 13 } }\\{ \cos ( a - \beta ) = 22 }\end{array} \right.$$

β، a نى يېشىش

$$\beta =2\pi n_{1}-i\ln(\frac{\sqrt{24395964603148870561481014759128391}+156250000000000000}{4254162297224853})+\pi \text{, }n_{1}\in \mathrm{Z}\text{, }a\in \cup n_{3},2\pi n_{1}+2\pi n_{3}-i\ln(\frac{\sqrt{24395964603148870561481014759128391}+156250000000000000}{4254162297224853})-i\ln(22-\sqrt{483})+\pi \text{, }n_{1}\in \mathrm{Z}$$

$$\beta =2\pi n_{1}-i\ln(\frac{\sqrt{24395964603148870561481014759128391}+156250000000000000}{4254162297224853})+\pi \text{, }n_{1}\in \mathrm{Z}\text{, }a\in \cup n_{4},2\pi n_{1}+2\pi n_{4}-i\ln(\frac{\sqrt{24395964603148870561481014759128391}+156250000000000000}{4254162297224853})-i\ln(\sqrt{483}+22)+\pi \text{, }n_{1}\in \mathrm{Z}$$

$$\beta =2\pi n_{2}-i\ln(\frac{156250000000000000-\sqrt{24395964603148870561481014759128391}}{4254162297224853})+\pi \text{, }n_{2}\in \mathrm{Z}\text{, }a\in \cup n_{3},2\pi n_{2}+2\pi n_{3}-i\ln(\frac{156250000000000000-\sqrt{24395964603148870561481014759128391}}{4254162297224853})-i\ln(22-\sqrt{483})+\pi \text{, }n_{2}\in \mathrm{Z}$$

$$\beta =2\pi n_{2}-i\ln(\frac{156250000000000000-\sqrt{24395964603148870561481014759128391}}{4254162297224853})+\pi \text{, }n_{2}\in \mathrm{Z}\text{, }a\in \cup n_{4},2\pi n_{2}+2\pi n_{4}-i\ln(\sqrt{483}+22)-i\ln(\frac{156250000000000000-\sqrt{24395964603148870561481014759128391}}{4254162297224853})+\pi \text{, }n_{2}\in \mathrm{Z}$$