c^2=1+sinθ+sin^2θ/2! хәл итегез

$$c ^ { 2 } = 1 + \sin \theta + \frac { \sin ^ { 2 } \theta } { 2 ! }$$

c өчен чишелеш (complex solution)

$$c=-\frac{\sqrt{4\sin(\theta )-\cos(2\theta )+5}}{2}$$

$$c=\frac{\sqrt{4\sin(\theta )-\cos(2\theta )+5}}{2}$$

c өчен чишелеш

$$c=\frac{\sqrt{2\left(\left(\sin(\theta )\right)^{2}+2\sin(\theta )+2\right)}}{2}$$

$$c=-\frac{\sqrt{2\left(\left(\sin(\theta )\right)^{2}+2\sin(\theta )+2\right)}}{2}$$

θ өчен чишелеш

$$\theta =\pi +2\pi n_{22}+arcSin(1+\left(-1\right)\left(-1+2c^{2}\right)^{\frac{1}{2}})\text{, }n_{22}\in \mathrm{Z}$$

$$\theta =\left(-1\right)arcSin(1+\left(-1\right)\left(-1+2c^{2}\right)^{\frac{1}{2}})+2\pi n_{21}\text{, }n_{21}\in \mathrm{Z}$$

$$\theta =\pi +2\pi n_{48}+arcSin(1+\left(-1+2c^{2}\right)^{\frac{1}{2}})\text{, }n_{48}\in \mathrm{Z}$$

$$\theta =\left(-1\right)arcSin(1+\left(-1+2c^{2}\right)^{\frac{1}{2}})+2\pi n_{47}\text{, }n_{47}\in \mathrm{Z}$$