แก้โจทย์ {l}{tan^2(A)-sin^2(A)=sin^4(A)sec^2(A)}{{(1+cot(A)-csc(A))}{(1+tan(A)+sec(A))}=2}{a=1}{b=a}{text{Solvefor}ctext{where}}{c=b}

$$\left. \begin{array} { l } { \tan^{2}(A) - \sin^{2}(A) = \sin^{4}(A) \sec^{2}(A) }\\ { {(1 + \cot(A) - \csc(A))} {(1 + \tan(A) + \sec(A))} = 2 }\\ { a = 1 }\\ { b = a }\\ { \text{Solve for } c \text{ where} } \\ { c = b } \end{array} \right.$$

หาค่า A, a, b, c

$$A\in \left(2\pi n_{1}+\pi ,2\pi n_{1}+\frac{3\pi }{2}\right)\cup \left(2\pi n_{1}+\frac{3\pi }{2},2\pi n_{1}+2\pi \right)\text{, }n_{1}\in \mathrm{Z}\text{, }a=1\text{, }b=1\text{, }c=1$$

$$A\in \left(2\pi n_{2},2\pi n_{2}+\frac{\pi }{2}\right)\cup \left(2\pi n_{2}+\frac{\pi }{2},2\pi n_{2}+\pi \right)\text{, }n_{2}\in \mathrm{Z}\text{, }a=1\text{, }b=1\text{, }c=1$$