Zgjidh x^2>1/2

$$x ^ { 2 } > \frac { 1 } { 2 }$$

Gjej x

$$x\in \left(-\infty,-\frac{\sqrt{2}}{2}\right)\cup \left(\frac{\sqrt{2}}{2},\infty\right)$$

Hapat e zgjidhjes

Llogarit rrënjën katrore të \frac{1}{2} dhe merr \frac{\sqrt{2}}{2}. Rishkruaj \frac{1}{2} si \left(\frac{\sqrt{2}}{2}\right)^{2}.

$$x^{2}>\left(\frac{\sqrt{2}}{2}\right)^{2}$$

Mosbarazimi qëndron për |x|>\frac{\sqrt{2}}{2}.

$$|x|>\frac{\sqrt{2}}{2}$$

Rishkruaj |x|>\frac{\sqrt{2}}{2} si x<-\frac{\sqrt{2}}{2}\text{; }x>\frac{\sqrt{2}}{2}.

$$x<-\frac{\sqrt{2}}{2}\text{; }x>\frac{\sqrt{2}}{2}$$