Rešite f(11/2)=(11/2)-1/2(1frac{1{2})^2-(11/2)^2}=

$$f ( 1 \frac { 1 } { 2 } ) = \frac { ( 1 \frac { 1 } { 2 } ) - 1 } { 2 ( 1 \frac { 1 } { 2 } ) ^ { 2 } - ( 1 \frac { 1 } { 2 } ) ^ { 2 } } =$$

Ovrednoti

$$\frac{2}{9}\approx 0,222222222$$

Koraki rešitve

Pomnožite 1 in 2, da dobite 2.

$$\frac{\frac{2+1}{2}-1}{2\times \left(\frac{1\times 2+1}{2}\right)^{2}-\left(\frac{1\times 2+1}{2}\right)^{2}}$$

Seštejte 2 in 1, da dobite 3.

$$\frac{\frac{3}{2}-1}{2\times \left(\frac{1\times 2+1}{2}\right)^{2}-\left(\frac{1\times 2+1}{2}\right)^{2}}$$

Odštejte 1 od \frac{3}{2}, da dobite \frac{1}{2}.

$$\frac{\frac{1}{2}}{2\times \left(\frac{1\times 2+1}{2}\right)^{2}-\left(\frac{1\times 2+1}{2}\right)^{2}}$$

Pomnožite 1 in 2, da dobite 2.

$$\frac{\frac{1}{2}}{2\times \left(\frac{2+1}{2}\right)^{2}-\left(\frac{1\times 2+1}{2}\right)^{2}}$$

Seštejte 2 in 1, da dobite 3.

$$\frac{\frac{1}{2}}{2\times \left(\frac{3}{2}\right)^{2}-\left(\frac{1\times 2+1}{2}\right)^{2}}$$

Izračunajte potenco \frac{3}{2} števila 2, da dobite \frac{9}{4}.

$$\frac{\frac{1}{2}}{2\times \frac{9}{4}-\left(\frac{1\times 2+1}{2}\right)^{2}}$$

Pomnožite 2 in \frac{9}{4}, da dobite \frac{9}{2}.

$$\frac{\frac{1}{2}}{\frac{9}{2}-\left(\frac{1\times 2+1}{2}\right)^{2}}$$

Pomnožite 1 in 2, da dobite 2.

$$\frac{\frac{1}{2}}{\frac{9}{2}-\left(\frac{2+1}{2}\right)^{2}}$$

Seštejte 2 in 1, da dobite 3.

$$\frac{\frac{1}{2}}{\frac{9}{2}-\left(\frac{3}{2}\right)^{2}}$$

Izračunajte potenco \frac{3}{2} števila 2, da dobite \frac{9}{4}.

$$\frac{\frac{1}{2}}{\frac{9}{2}-\frac{9}{4}}$$

Odštejte \frac{9}{4} od \frac{9}{2}, da dobite \frac{9}{4}.

$$\frac{\frac{1}{2}}{\frac{9}{4}}$$

Delite \frac{1}{2} s/z \frac{9}{4} tako, da pomnožite \frac{1}{2} z obratno vrednostjo \frac{9}{4}.

$$\frac{1}{2}\times \frac{4}{9}$$

Pomnožite \frac{1}{2} in \frac{4}{9}, da dobite \frac{2}{9}.

$$\frac{2}{9}$$

Faktoriziraj

$$\frac{2}{3 ^ {2}} = 0,2222222222222222$$