Rešite C=1+tan(2pi/9)^2/sqrt{(4^2+1)}

$$C = \frac { 1 + \tan ( 2 \frac { \pi } { 9 } ) ^ { 2 } } { \sqrt { ( 4 ^ { 2 } + 1 ) } }$$

Rešitev za C

$$C=\frac{170408819104184715837886196294401\sqrt{17}}{1700000000000000000000000000000000}\approx 0,413302095$$

Koraki za reševanje linearnih enačb

Evaluate trigonometric functions in the problem

$$C = \frac{1 + 0,8390996311772799 ^ {2}}{\sqrt{{(4 ^ {2} + 1)}}}$$

Izračunajte potenco 0,8390996311772799 števila 2, da dobite 0,70408819104184715837886196294401.

$$C=\frac{1+0,70408819104184715837886196294401}{\sqrt{4^{2}+1}}$$

Seštejte 1 in 0,70408819104184715837886196294401, da dobite 1,70408819104184715837886196294401.

$$C=\frac{1,70408819104184715837886196294401}{\sqrt{4^{2}+1}}$$

Izračunajte potenco 4 števila 2, da dobite 16.

$$C=\frac{1,70408819104184715837886196294401}{\sqrt{16+1}}$$

Seštejte 16 in 1, da dobite 17.

$$C=\frac{1,70408819104184715837886196294401}{\sqrt{17}}$$

Racionalizirajte imenovalec \frac{1,70408819104184715837886196294401}{\sqrt{17}} tako, da pomnožite števec in imenovalec s \sqrt{17}.

$$C=\frac{1,70408819104184715837886196294401\sqrt{17}}{\left(\sqrt{17}\right)^{2}}$$

Kvadrat vrednosti \sqrt{17} je 17.

$$C=\frac{1,70408819104184715837886196294401\sqrt{17}}{17}$$

Delite 1,70408819104184715837886196294401\sqrt{17} s/z 17, da dobite \frac{170408819104184715837886196294401}{1700000000000000000000000000000000}\sqrt{17}.

$$C=\frac{170408819104184715837886196294401}{1700000000000000000000000000000000}\sqrt{17}$$

Dodeli C

$$C≔\frac{170408819104184715837886196294401\sqrt{17}}{1700000000000000000000000000000000}$$