Rešite 6x^2-7bx+2b^2+6geq0

$$6 x ^ { 2 } - 7 b x + 2 b ^ { 2 } + 6 \geq 0$$

Rešitev za x

$$\left\{\begin{matrix}x\in \mathrm{R}\text{, }&|b|\leq 12\\x\in (-\infty,\frac{-\sqrt{b^{2}-144}+7b}{12}]\cup [\frac{\sqrt{b^{2}-144}+7b}{12},\infty)\text{, }&|b|\geq 12\end{matrix}\right,$$

Rešitev za b

$$\left\{\begin{matrix}b\in \mathrm{R}\text{, }&|x|\leq 4\sqrt{3}\\b\in (-\infty,\frac{-\sqrt{x^{2}-48}+7x}{4}]\cup [\frac{\sqrt{x^{2}-48}+7x}{4},\infty)\text{, }&|x|\geq 4\sqrt{3}\end{matrix}\right,$$