Rešite (32*25)*(10^-10*10^-11)

$$( 32 \times 25 ) \times ( 10 ^ { - 10 } \times 10 ^ { - 11 } )$$

Ovrednoti

$$\frac{1}{1250000000000000000}=8 \cdot 10^{-19}$$

Koraki rešitve

Če želite pomnožiti potence z isto osnovo, seštejte njihove eksponente. Seštejte -10 in -11, da dobite -21.

$$32\times 25\times 10^{-21}$$

Pomnožite 32 in 25, da dobite 800.

$$800\times 10^{-21}$$

Izračunajte potenco 10 števila -21, da dobite \frac{1}{1000000000000000000000}.

$$800\times \frac{1}{1000000000000000000000}$$

Pomnožite 800 in \frac{1}{1000000000000000000000}, da dobite \frac{1}{1250000000000000000}.

$$\frac{1}{1250000000000000000}$$

Faktoriziraj

$$\frac{1}{2 ^ {16} \cdot 5 ^ {19}} = 8 \times 10^{-19}$$