Rešite {left(3/21/4+1/510/3right)}^2+1=

$${ \left( \frac{ 3 }{ 2 } \frac{ 1 }{ 4 } + \frac{ 1 }{ 5 } \frac{ 10 }{ 3 } \right) }^{ 2 } +1=$$

Ovrednoti

$$\frac{1201}{576}\approx 2,085069444$$

Koraki rešitve

Pomnožite \frac{3}{2} in \frac{1}{4}, da dobite \frac{3}{8}.

$$\left(\frac{3}{8}+\frac{1}{5}\times \frac{10}{3}\right)^{2}+1$$

Pomnožite \frac{1}{5} in \frac{10}{3}, da dobite \frac{2}{3}.

$$\left(\frac{3}{8}+\frac{2}{3}\right)^{2}+1$$

Seštejte \frac{3}{8} in \frac{2}{3}, da dobite \frac{25}{24}.

$$\left(\frac{25}{24}\right)^{2}+1$$

Izračunajte potenco \frac{25}{24} števila 2, da dobite \frac{625}{576}.

$$\frac{625}{576}+1$$

Seštejte \frac{625}{576} in 1, da dobite \frac{1201}{576}.

$$\frac{1201}{576}$$

Faktoriziraj

$$\frac{1201}{2 ^ {6} \cdot 3 ^ {2}} = 2\frac{49}{576} = 2,0850694444444446$$