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\frac{\mathrm{d}}{\mathrm{d}\alpha }(\sin(\alpha ))=\left(\lim_{h\to 0}\frac{\sin(\alpha +h)-\sin(\alpha )}{h}\right)
Za funkcijo f\left(x\right) je odvod limita funkcije \frac{f\left(x+h\right)-f\left(x\right)}{h}, saj gre h v 0, če ta limita obstaja.
\lim_{h\to 0}\frac{\sin(h+\alpha )-\sin(\alpha )}{h}
Uporabite formulo za sinus vsote.
\lim_{h\to 0}\frac{\sin(\alpha )\left(\cos(h)-1\right)+\cos(\alpha )\sin(h)}{h}
Faktorizirajte \sin(\alpha ).
\left(\lim_{h\to 0}\sin(\alpha )\right)\left(\lim_{h\to 0}\frac{\cos(h)-1}{h}\right)+\left(\lim_{h\to 0}\cos(\alpha )\right)\left(\lim_{h\to 0}\frac{\sin(h)}{h}\right)
Znova napišite limito.
\sin(\alpha )\left(\lim_{h\to 0}\frac{\cos(h)-1}{h}\right)+\cos(\alpha )\left(\lim_{h\to 0}\frac{\sin(h)}{h}\right)
Uporabite dejstvo, da je \alpha konstanta, kadar računate limite, saj gre h v 0.
\sin(\alpha )\left(\lim_{h\to 0}\frac{\cos(h)-1}{h}\right)+\cos(\alpha )
Limita \lim_{\alpha \to 0}\frac{\sin(\alpha )}{\alpha } je 1.
\left(\lim_{h\to 0}\frac{\cos(h)-1}{h}\right)=\left(\lim_{h\to 0}\frac{\left(\cos(h)-1\right)\left(\cos(h)+1\right)}{h\left(\cos(h)+1\right)}\right)
Če želite ovrednotiti limite \lim_{h\to 0}\frac{\cos(h)-1}{h}, najprej pomnožite števec in imenovalec s \cos(h)+1.
\lim_{h\to 0}\frac{\left(\cos(h)\right)^{2}-1}{h\left(\cos(h)+1\right)}
Pomnožite \cos(h)+1 s/z \cos(h)-1.
\lim_{h\to 0}-\frac{\left(\sin(h)\right)^{2}}{h\left(\cos(h)+1\right)}
Uporabite Pitagorovo identiteto.
\left(\lim_{h\to 0}-\frac{\sin(h)}{h}\right)\left(\lim_{h\to 0}\frac{\sin(h)}{\cos(h)+1}\right)
Znova napišite limito.
-\left(\lim_{h\to 0}\frac{\sin(h)}{\cos(h)+1}\right)
Limita \lim_{\alpha \to 0}\frac{\sin(\alpha )}{\alpha } je 1.
\left(\lim_{h\to 0}\frac{\sin(h)}{\cos(h)+1}\right)=0
Uporabite dejstvo, da je funkcija \frac{\sin(h)}{\cos(h)+1} zvezna pri 0.
\cos(\alpha )
Vstavite vrednost 0 v izraz \sin(\alpha )\left(\lim_{h\to 0}\frac{\cos(h)-1}{h}\right)+\cos(\alpha ).