Rešite 7/11leq7/3(1)+5leq-1

$$\frac{ 7 }{ 11 } \leq \frac{ 7 }{ 3(1)+5 } \leq -1$$

Preveri

Koraki rešitve

Pomnožite 3 in 1, da dobite 3.

$$\frac{7}{11}\leq \frac{7}{3+5}\text{ and }\frac{7}{3\times 1+5}\leq -1$$

Seštejte 3 in 5, da dobite 8.

$$\frac{7}{11}\leq \frac{7}{8}\text{ and }\frac{7}{3\times 1+5}\leq -1$$

Najmanjši skupni mnogokratnik 11 in 8 je 88. Pretvorite \frac{7}{11} in \frac{7}{8} v ulomke z imenovalcem 88.

$$\frac{56}{88}\leq \frac{77}{88}\text{ and }\frac{7}{3\times 1+5}\leq -1$$

Primerjajte \frac{56}{88} in \frac{77}{88}.

$$\text{true}\text{ and }\frac{7}{3\times 1+5}\leq -1$$

Pomnožite 3 in 1, da dobite 3.

$$\text{true}\text{ and }\frac{7}{3+5}\leq -1$$

Seštejte 3 in 5, da dobite 8.

$$\text{true}\text{ and }\frac{7}{8}\leq -1$$

Pretvorite -1 v ulomek -\frac{8}{8}.

$$\text{true}\text{ and }\frac{7}{8}\leq -\frac{8}{8}$$

Primerjajte \frac{7}{8} in -\frac{8}{8}.

$$\text{true}\text{ and }\text{false}$$

Konjunkcija vrednosti \text{true} in \text{false} je \text{false}.

$$\text{false}$$