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\frac{\frac{\left(-\frac{1}{6}\right)^{2}}{\frac{5}{6}}-\sqrt{\frac{1}{9}}}{\sqrt[3]{\frac{1}{8}}+\left(1-\frac{1}{2}\right)^{2}\times \frac{9}{8}}
Odštejte \frac{2}{3} od \frac{1}{2}, da dobite -\frac{1}{6}.
\frac{\frac{\frac{1}{36}}{\frac{5}{6}}-\sqrt{\frac{1}{9}}}{\sqrt[3]{\frac{1}{8}}+\left(1-\frac{1}{2}\right)^{2}\times \frac{9}{8}}
Izračunajte potenco -\frac{1}{6} števila 2, da dobite \frac{1}{36}.
\frac{\frac{1}{36}\times \frac{6}{5}-\sqrt{\frac{1}{9}}}{\sqrt[3]{\frac{1}{8}}+\left(1-\frac{1}{2}\right)^{2}\times \frac{9}{8}}
Delite \frac{1}{36} s/z \frac{5}{6} tako, da pomnožite \frac{1}{36} z obratno vrednostjo \frac{5}{6}.
\frac{\frac{1}{30}-\sqrt{\frac{1}{9}}}{\sqrt[3]{\frac{1}{8}}+\left(1-\frac{1}{2}\right)^{2}\times \frac{9}{8}}
Pomnožite \frac{1}{36} in \frac{6}{5}, da dobite \frac{1}{30}.
\frac{\frac{1}{30}-\frac{1}{3}}{\sqrt[3]{\frac{1}{8}}+\left(1-\frac{1}{2}\right)^{2}\times \frac{9}{8}}
Znova napišite kvadratni koren deljenja \frac{1}{9} kot deljenje kvadratnih korenov \frac{\sqrt{1}}{\sqrt{9}}. Vzemite kvadratni koren števca in imenovalca.
\frac{-\frac{3}{10}}{\sqrt[3]{\frac{1}{8}}+\left(1-\frac{1}{2}\right)^{2}\times \frac{9}{8}}
Odštejte \frac{1}{3} od \frac{1}{30}, da dobite -\frac{3}{10}.
\frac{-\frac{3}{10}}{\frac{1}{2}+\left(1-\frac{1}{2}\right)^{2}\times \frac{9}{8}}
Izračunajte \sqrt[3]{\frac{1}{8}} in dobite \frac{1}{2}.
\frac{-\frac{3}{10}}{\frac{1}{2}+\left(\frac{1}{2}\right)^{2}\times \frac{9}{8}}
Odštejte \frac{1}{2} od 1, da dobite \frac{1}{2}.
\frac{-\frac{3}{10}}{\frac{1}{2}+\frac{1}{4}\times \frac{9}{8}}
Izračunajte potenco \frac{1}{2} števila 2, da dobite \frac{1}{4}.
\frac{-\frac{3}{10}}{\frac{1}{2}+\frac{9}{32}}
Pomnožite \frac{1}{4} in \frac{9}{8}, da dobite \frac{9}{32}.
\frac{-\frac{3}{10}}{\frac{25}{32}}
Seštejte \frac{1}{2} in \frac{9}{32}, da dobite \frac{25}{32}.
-\frac{3}{10}\times \frac{32}{25}
Delite -\frac{3}{10} s/z \frac{25}{32} tako, da pomnožite -\frac{3}{10} z obratno vrednostjo \frac{25}{32}.
-\frac{48}{125}
Pomnožite -\frac{3}{10} in \frac{32}{25}, da dobite -\frac{48}{125}.