Rešite 1/3*(3)^-1+025/frac{1{3}*(33/50-1)}=

$$\frac { \frac { 1 } { 3 } \cdot ( 3 ) ^ { - 1 } + 025 } { \frac { 1 } { 3 } \cdot ( \frac { 33 } { 50 } - 1 ) } =$$

Ovrednoti

$$-\frac{50}{51}\approx -0,980392157$$

Koraki rešitve

Izračunajte potenco 3 števila -1, da dobite \frac{1}{3}.

$$\frac{\frac{1}{3}\times \frac{1}{3}+0\times 25}{\frac{1}{3}\left(\frac{33}{50}-1\right)}$$

Pomnožite \frac{1}{3} in \frac{1}{3}, da dobite \frac{1}{9}.

$$\frac{\frac{1}{9}+0\times 25}{\frac{1}{3}\left(\frac{33}{50}-1\right)}$$

Pomnožite 0 in 25, da dobite 0.

$$\frac{\frac{1}{9}+0}{\frac{1}{3}\left(\frac{33}{50}-1\right)}$$

Seštejte \frac{1}{9} in 0, da dobite \frac{1}{9}.

$$\frac{\frac{1}{9}}{\frac{1}{3}\left(\frac{33}{50}-1\right)}$$

Odštejte 1 od \frac{33}{50}, da dobite -\frac{17}{50}.

$$\frac{\frac{1}{9}}{\frac{1}{3}\left(-\frac{17}{50}\right)}$$

Pomnožite \frac{1}{3} in -\frac{17}{50}, da dobite -\frac{17}{150}.

$$\frac{\frac{1}{9}}{-\frac{17}{150}}$$

Delite \frac{1}{9} s/z -\frac{17}{150} tako, da pomnožite \frac{1}{9} z obratno vrednostjo -\frac{17}{150}.

$$\frac{1}{9}\left(-\frac{150}{17}\right)$$

Pomnožite \frac{1}{9} in -\frac{150}{17}, da dobite -\frac{50}{51}.

$$-\frac{50}{51}$$

Faktoriziraj

$$-\frac{50}{51} = -0,9803921568627451$$