Решить R_{1}=1140*10^-6muOmegaquadR_{2}=1000*10^-6muOmegaquadc_{1}=01mu5

$$R _ { 1 } = 1140 \times 10 ^ { - 6 } \mu \Omega \quad R _ { 2 } = 1000 \times 10 ^ { - 6 } \mu \Omega \quad c _ { 1 } = 01 \mu 5$$

Вычислить (комплексное решение)

$$R_{1}=\frac{57R_{2}\Omega \mu }{50000}\text{ and }\frac{57R_{2}\Omega \mu }{50000}=\frac{c_{1}\Omega \mu }{1000}\text{ and }c_{1}\Omega \mu =0$$

Решение для μ

$$\left\{\begin{matrix}\mu =0\text{, }&R_{1}=0\\\mu \in \mathrm{R}\text{, }&\left(\Omega =0\text{ and }R_{1}=0\right)\text{ or }\left(c_{1}=0\text{ and }R_{2}=0\text{ and }R_{1}=0\right)\end{matrix}\right,$$

Решение для Ω

$$\left\{\begin{matrix}\Omega =0\text{, }&R_{1}=0\\\Omega \in \mathrm{R}\text{, }&\left(\mu =0\text{ and }R_{1}=0\right)\text{ or }\left(c_{1}=0\text{ and }R_{2}=0\text{ and }R_{1}=0\right)\end{matrix}\right,$$